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3 years ago

Someone help please ASAP. In∆ABC, m a) How are the measures of m b) Solve for x:

1 answer:

4 0

$3x+9+8x+11+5x-8=180\\
16x=168\\
x=10.5\\\\
m\angle BAC=3\cdot10.5+9=40.5\\
m\angle ABC=8\cdot10.5+11=95\\
m\angle BCA=5\cdot10.5-8=44.5\\\\
$

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Answer:

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Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

$(x-h)^2 +(y-k)^2 = r^2$

From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this: $(x+8)^2 +(y-4)^2 = r^2$

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for $r^2$

$(-4+8)^2 +(7-4)^2 =25= r^2$

So then $r = \sqrt{25}=5$

And if we replace the second point we got this:

$(-13+8)^2 +(4-4)^2 = 25 =r^2$

And for the third point we have:

$(-8+8)^2 +(-1-4)^2 = 25 =r^2$

And we got the same result.

So then our final equation is given:

$(x+8)^2 +(y-4)^2 = 25$

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