Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
x= 12
Step-by-step explanation:
2(x-7) = 10
Distribute the 2. 2x-14 = 10
Add the 14 onto both sides to cancel it out on the original side and following the rules- the same must be done to the other side. 2x-14 (+14) = 10+14 -----> 2x = 24
Divide both sides by 2 to get the X alone. 2x/2 = 24/2 ---------> x= 12
First of all that is NOT math and second of al that is not english
4 1/4, 4 5/12, 4 2/3. Not sure if there is suppose to be a 4 in front of the 5/12 but if there is this is how it should be ordered
