Enter the number of complex zeros for the polynomial function in the box.
1 answer:
Given polynomial function:
.
We need to apply Descartes' rule of sign to identify the number of complex roots.
The given polynomial is f(x)=x^3-96x^2+400
Let us see the number of sign changes in f(x)
There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.
Now, let us see the number of sign changes in f(-x)
f(-x)=-x^3-96x^2+400
There are only one sign change. Hence, there will be 1 negative roots.
The degree of the polynomial is 3.
Hence, there will be exactly 3 zeros.
<em>Therefore, the possible numbers of zeros are:</em>
<em>2 positive, 1 negative and 0 complex</em>
<em>0 positive, 1 negative and 2 complex.</em>
Let us see the graph:
In the graph, we can see that the graph cuts the x axis at three points (2 positive, 1 negative points).
<h3>Hence, the number of complex zeros for the given polynomial is zero.</h3>
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<h2>Answer with explanation:</h2>
Let be the population mean.
By considering the given information , we have
Null hypothesis :
Alternative hypothesis :
Since alternative hypothesis is right-tailed , so the test is a right-tailed test.
Given : Sample size : n=16 , which is a small sample , so we use t-test.
Sample mean: ;
Standard deviation:
Test statistic for population mean:
i.e.
Using the standard normal distribution table of t , we have
Critical value for :
Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.