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3 years ago

How might foreign investment be problematic for a transitioning economy?

Mathematics

2 answers:

nika2105 [10]3 years ago

7 0

It may be difficult to adjust to another nation’s influence. Just got it right on the quiz.

KengaRu [80]3 years ago

3 0

The foreign investment is problematic for the economy of a transitioning country because it provides profit to the foreign investors only. They use cheap labor of the developing country. Moreover, the local producers and investors are directly harmed. The major profits are going in the pockets of the other nation's investors. This also causes inflation in the country.

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Given: ABCD trapezoid, BK ⊥ AD , AB=DC AB=8, AK=4 Find: m∠A, m∠B

Elis [28]

Answer:

$m\angle B=m\angle C=120^{\circ}$

$m\angle A=m\angle D=60^{\circ}$

Step-by-step explanation:

Trapezoid ABCD is isosceles trapezoid, because AB = CD (given). In isosceles trapezoid, angles adjacent to the bases are congruent, then

$\angle A\cong \angle D;$
$\angle B\cong \angle C.$

Since BK ⊥ AD, the triangle ABK is right triangle. In this triangle, AB = 8, AK = 4. Note that the hypotenuse AB is twice the leg AK:

$AB=2AK.$

If in the right triangle the hypotenuse is twice the leg, then the angle opposite to this leg is 30°, so,

$m\angle ABK=30^{\circ}$

Since BK ⊥ AD, then BK ⊥ BC and

$m\angle KBC=90^{\circ}$

Thus,

$m\angle B=30^{\circ}+90^{\circ}=120^{\circ}\\ \\m\angle B=m\angle C=120^{\circ}$

Now,

$m\angle A=m\angle D=180^{\circ}-120^{\circ}=60^{\circ}$

7 0

2 years ago

I am confused on how to do this.

Charra [1.4K]

The answer is A.....

6 0

3 years ago

X + y - 6 = 0 x - y = 0

hram777 [196]

3 + 3 - 6 = 0
3 - 3 = 0

5 0

3 years ago

Read 2 more answers

Evaluating 4 + 5 over 2 times 2 minus 7

alexgriva [62]

The answer to 4+5/2•2-7 is -3

8 0

3 years ago

Read 2 more answers

2x+8y=3 and 4x-3y=2 value of x and y.. plzz help me

lesya692 [45]

Answer:

Set a system of equations:

$\left \{ {{2x+8y=3} \atop {4x-3y=2}} \right.$

Multiply the whole upper equation by 2 and the whole bottom equation by 1 so their x-value equals:

$\left \{ {{2(2)x+8(2)y=3(2)} \atop {4(1)x-3(1)y=2(1)}} \right.\\\\=\left \{ {{4x+16y=6} \atop {4x-3y=2}} \right.$

Subtract the upper equation by the bottom equation & solve for y:

$(4x-4x)+(16y-(-3y))=6-2\\\\19y=4\\\\y=\frac{4}{19}$

Substitute in the y-value to a equation to find x:

$2x+8y=3\\\\2x+8(\frac{4}{19} )=3\\\\2x=3-\frac{32}{19} =\frac{57}{19} -\frac{32}{19} =\frac{25}{19} \\\\x=\frac{\frac{25}{19}}{2} =\frac{25}{19}*\frac{1}{2} =\frac{25}{38}$

Therefore, the answer would be:

$\left \{ {{y=\frac{4}{19} } \atop {x=\frac{25}{38} }} \right.$

6 0

3 years ago