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olga nikolaevna [1]
3 years ago
12

What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction) and (one-third, S

tartFraction 11 Over 12 EndFraction) in slope-intercept form? y = one-half x minus three-fourths y = one-half x + three-fourths y = three-fourths x minus one-half y = three-fourths x + one-halfy = one-half x minus three-fourths
y = one-half x + three-fourths
y = three-fourths x minus one-half
y = three-fourths x + one-half
Mathematics
2 answers:
Neporo4naja [7]3 years ago
8 0

Answer:

  y = one-half x + three-fourths

Step-by-step explanation:

The 2-point form of the equation of a line can be used for starters.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values

  y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little

  y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...

  y = 1/2x -4/20 +19/20

  y = 1/2x +15/20

  y = 1/2x +3/4 . . . . line in slope-intercept form

Lilit [14]3 years ago
6 0

Answer:

y = 1/2x +3/4

Step-by-step explanation:

got it right

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Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

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Step-by-step explanation:

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