3r = 10 + 5s , <span>r = 10
plug in the value of "r" into the equation:
3(10) = 10 +5s
30 = 10 + 5s
subtract 10 from both sides:
20 = 5s
divide both sides by 5:
4 = s
s = 4</span>
Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
Answer:
See below.
Step-by-step explanation:
1a)
<u>Angles:</u>
<u>Add:</u>
<u>Subtract:</u>
Angle a: 132.
1b)
To get angle h above 180°, <u>We need to add h + 164:</u>
h = 110.
This is how to get h over 180°.
The answer is 20. you'll have to multiply 10 times 3 and get 30. Then you'll subtract the 10 from the 30 and get 20
Step-by-step explanation:
The lines have different slopes
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