All categories

3 years ago

Translate each of the following research questions into appropriate H0 and Ha.

Mathematics

1 answer:

Mandarinka [93]3 years ago

7 0

Answer:

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

Step-by-step explanation:

We have to build appropriate null and alternate hypothesis for the given scenarios.

a) Population mean, μ = $62,500 per year

The market research wants to find whether the mean household income of mall shoppers is higher than that of the general population.

$H_{0}: \mu = 62500\text{ dollars per year}\\H_A: \mu > 62500\text{ dollars per year}$

We would use one-tail(right) test to perform this hypothesis.

b) Population mean, μ = 2.6 hours

The company want to know the average time to respond to trouble calls is different or not.

$H_{0}: \mu = 2.6\text{ hours}\\H_A: \mu \neq 2.6\text{ hours}$

We would use two-tail test to perform this hypothesis.

You might be interested in

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events A and B are independent.

Step-by-step explanation:

The events are defined as follows:

A = a student in the class has a sister

B = a student has a brother

The information provided is:

N = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event X provided that another event Y has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events X and Y are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event A and B as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of B given A as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events A and B are independent.

6 0

3 years ago

Which fraction, decimal number, and percent are equivalent?

uranmaximum [27]

Answer:

A. 2/5, 0.40, 40%

Step-by-step explanation:

To turn a fractions into a decimal divided the numerator by the denominator. 2/5=0.40.

8 0

3 years ago

A grain of sand has a diameter of 0.049 millimeters. Write 0.049 in words.

Sunny_sXe [5.5K]

Forty-nine thousandths

5 0

3 years ago

Read 2 more answers

HELP PLS- 50pts!!! (This is Linear programming)- The amphitheater has two types of tickets available, reserved seats and lawn se

Alenkinab [10]

The Maximum profit occurs when 20,000 reserved seats are sold and the profit is $1,300,000

3 0

3 years ago

Solve: 3n - 6 = -8(6 +5n) and explain how to solve it

hjlf

Answer:

Step-by-step explanation:

First use distributive property: a(b + c) = a*b + a*c

3n - 6 = -8(6 + 5n)

3n - 6 = 6 * (-8) + 5n *(-8)

3n - 6 = -48 - 40n

Now add 40n to both sides

3n - 6 + 40n = -48 - 40n + 40n

43n - 6 = -48

Now add 6 to both sides

43n - 6 + 6 = -48 + 6

43n = -42

n = -42 /43

4 0

2 years ago

Read 2 more answers