All categories

3 years ago

Quadtratic equation for 8x^2+3x+3=0

Mathematics

1 answer:

choli [55]3 years ago

6 0

Answer:

The answer is x=-3±i√87/16

Step-by-step explanation:

You might be interested in

What is the solution to y-7>3+2y

Alex17521 [72]

Solving:

-7 + y = 3 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.

-7 + y + -2y = 3 + 2y + -2y

Combine like terms: y + -2y = -1y

-7 + -1y = 3 + 2y + -2y

Combine like terms: 2y + -2y = 0

-7 + -1y = 3 + 0

-7 + -1y = 3

Add '7' to each side of the equation.

-7 + 7 + -1y = 3 + 7

Combine like terms: -7 + 7 = 0

0 + -1y = 3 + 7

-1y = 3 + 7

Combine like terms: 3 + 7 = 10

-1y = 10

Divide each side by '-1'.

y = -10

Hope it helps. (:

6 0

3 years ago

Find the slope of the line that passes through (6, 68) and (54,-7)

soldi70 [24.7K]

Answer:

-25/16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-7-68)/(54-6)

m=-75/48

m=-25/16

7 0

2 years ago

Read 2 more answers

Need help solving pleaseee!!!

natta225 [31]

Answer:

Step-by-step explanation:

50.

line AB that has the points (2,5) and (9,2) hhas the slope

m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7

Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).

Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or

you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4

51.

line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2

Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5

y-3 = -2/5 (x-1)

5 0

3 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

A large tank holds 1.9 x 10^7 gallons of oil. How much oil can be stored in 9 tanks. Write your answer in scientific notation.

bearhunter [10]

Answer:

1.71 × 10^8 gallons

Step-by-step explanation:

1.9 × 10^7 = 19,000,000

19,000,000 × 9 = 171,000,000

171,000,000 in scientific notation is 1.71 × 10^8

5 0

3 years ago