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Korolek [52]
3 years ago
15

Can you help me please 15=3-4x

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

Answer:add

Step-by-step explanation:then switch

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I need help with this question this is new to me
Romashka-Z-Leto [24]

Answer:

kuhaa ka timbangan

Step-by-step explanation:

1/4 ang kilo ng tilapya

7 0
3 years ago
What is the surface area of the rectangular<br> prism shown by the net?
brilliants [131]

Answer:

80

Step-by-step explanation:

There are four 4 by 3 rectangles, so I did 4x3 and got 12, then multiplied by 4 to get 48.  There are also two 4 by 4 squares, so 4x4=16 and 16x2=32

32+48=80

8 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
Can people help me please to find the volume about question number 10 please and tell me the answer step by step please I need h
Alecsey [184]
#10
Volume of a cylinder: \pir²h

Plug the numbers in.

\pi3²15 = <span>424
</span>
The volume of the pipe is 424 cm³.
7 0
3 years ago
Identify proportional realationships from graphs<br> There’s also a none option
kkurt [141]

Answer:

B is one is there anymore options

Step-by-step explanation:

3 0
2 years ago
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