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2 years ago

PLEASE LOOK AT PICURE!!! I WILL MARK BRAINIEST TO WHOEVER IS CORRECT!!!

Mathematics

2 answers:

Mrac [35]2 years ago

6 0

Answer:

6.708

Step-by-step explanation:

To calculate the distance between two given coordinates, there is a formula which is:

$d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

The coordinates provided, let's say

(-5, 9) (-2 , 3)

(x1, y1) (x2, y2)

Plug these values into the formula:

$\sqrt{(-2 - (-5))^2 + (3 - 9)^2}$

Simplify the values:

$\sqrt{(-2 + 5)^2 + (-6)^2}$

$\sqrt{(3)^2 + (-6)^2}$

$\sqrt{9 + 36}$

$d = \sqrt{45}$

Which gets us a decimal value of:

6.708

Hope this helps!

IgorC [24]2 years ago

3 0

Answer:

Step-by-step explanation:

7 I think

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2 years ago

Find the area of the circle to the nearest tenth. use 3.14 for pie

VikaD [51]

I assume that 4.4 is the diameter,please do correct me if i am wrong.

To get the area of the circle,the formula is 丌r^2

to find the radius,we need ro devide the diameter by 2

thus the equations is
$3.14 \times ({4.4 \div 2})^{2} \\ = 3.14 \times {2.2}^{2} \\ = 15.196 \\ = 15.2(correct \: to \: the \: nearest \: tenth)$
Therefore the answer is B.15.2

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3 0

3 years ago

Read 2 more answers

During a softball game, Sara threw 70 pitches. Of those pitches, 29 were strikes. What portion of the pitches that Sara threw we

EleoNora [17]

Answer: 0.414

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The thousands place is the third place.

5 0

3 years ago

Let u= <4,3>. Find the unit vector in the direction of u, and write your answer in component form.

aksik [14]

Take the vector u = <ux, uy> = <4, 3>.

Find the magnitude of u:

||u|| = sqrt[ (ux)^2 + (uy)^2]

||u|| = sqrt[ 4^2 + 3^2 ]

||u|| = sqrt[ 16 + 9 ]

||u|| = sqrt[ 25 ]

||u|| = 5

To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is

u/||u||

u * (1/||u||)

= <4, 3> * (1/5)

= <4/5, 3/5>

and there it is.

Writing it in component form:

= (4/5) * i + (3/5) * j

I hope this helps. =)

3 0

3 years ago

How to solver for 2y-1/3=5 prove: y= 8

nirvana33 [79]

3×2y-(1/3×3)=5×3
6y-1=15
6y-1+1=15+1
6y=16
y=8/3
Y cannot be 8

3 0

3 years ago