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3 years ago

I need some help with this

Mathematics

1 answer:

arsen [322]3 years ago

6 0

The tangent ratio is the ratio of opposite (500 ft) to adjacent (x).
tan(29°) = (500 ft)/x
x = (500 ft)/tan(29°)
x ≈ 902 ft

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3. During liftoff, a space shuttle accelerated to a speed of 862 m/s in 75 seconds. What was the

spin [16.1K]

11.493 or 11.5

Step-by-step explanation:

by dividing speed by time. 862/75

8 0

3 years ago

WILL MARK BRAINLIEST! PLEASE HELP MEH!<br><br><br> Find the area

grigory [225]

Area of trapezoid = $\frac{a+b}{2} (h)$
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3 years ago

What is the equation of the line that passes through the point (-1 ,6) and has a slope of 1

Harman [31]

Answer:

y=X+7

Step-by-step explanation:

(-1, 6)

1x up 1 over 1

y=mx+b

--------------------------

Plug 6 for y, and 1 for x.

Like this $6=x (+-)#$ #

We know x is -1. 6=(-1*1)+#

6=-1+#

y=X+7

-------------------

-1*1+7=6

6 0

3 years ago

IM BEING TIMED, WILL GIVE 25 POINTS (NEEDED WITHIN THE NEXT 20 MINUTES The graph g(x)=x^3-x is shown. (idk how to screenshot, so

saveliy_v [14]

Answer:

The function is

$f(x)=0.5x^3-3x^2+5.5x-2$

The graph is attached.

Step-by-step explanation:

We have a function g(x) and we need to graph a new function that is function of g(x).

The final function is

$f(x)=0.5\cdot g(x-2)+1$

We start by calculating g(x-2):

$g(x-2)=(x-2)^3-(x-2)\\\\g(x-2)=(x^3-6x^2+12x-8)-(x-2)\\\\g(x-2)=x^3-6x^2+11x-6$

Then, we can calculate f(x) as:

$f(x)=0.5\cdot g(x-2)+1\\\\g(x-2)=x^3-6x^2+11x-6\\\\\\f(x)=0.5(x^3-6x^2+11x-6)+1\\\\f(x)=0.5x^3-3x^2+5.5x-3+1\\\\\\f(x)=0.5x^3-3x^2+5.5x-2$

5 0

3 years ago

(4,5);y=3/2x+3 write an equation of the line that passes through the given point that is parallel to the given line

Aleonysh [2.5K]

Answer:

2x-3/y-5/37=0

Step-by-step explanation:

here, given equation of line is

y=3/2x+3

or,y(2x+3)=3

or,2x+3=3/y

or,2x-3/y+3=0...eqn(i)

equation of any line parallel to line (i) is

2x-3/y+k=0.. eqn(ii)

since, the line passes through (4,5)[replacing x=4 and y=5 in eqn(ii), we get]

2*4-3/5+k=0

or,8-3/5+k=0

or,40-3/5+k=0

or,k=-5/37

substituting the value of k=-5/37 in eqn(ii)

2x-3/y-5/37=0 is the required equation of line.

3 0

3 years ago