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ValentinkaMS [17]
3 years ago
8

Using the diagram, find the value of x.

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

If you could elaborate on what this is, I would be gladly to assist you, but there is uncertainty going on here. I apologise.

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Five boxes of candles contain a total of 60 candles. Each box holds the same number of candles. Complete the table and graph the
likoan [24]
They all each have 12 in a box
7 0
4 years ago
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What are the x intercepts of the graph of this function? Y=6*2+10x - 4
Damm [24]
X intercpe is when y=0

0=6x^2+10x-4
factor
0=2(3x^2+5x-2)
assume
0=3x^2+5x-2
0=(x+2)(3x-1)
set to zero
x+2=0
x=-2
3x-1=0
x=1/3

x intercepts are -2 and 1/3

D is answere
5 0
4 years ago
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A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
3 years ago
CAN YOU PLEASE WRITE THE EQUATION AND THE ANSWERS PLSS
Fofino [41]

Answer:

a. $17.50

b. $11.25

c. $5

Step-by-step explanation:

First, set up an equation:

20 - 1.25x = m

Now let's substitute in for x (which is how many snacks you buy) to solve for m (the amount of money you have left):

20 - 1.25 ( 2 ) = m

20 - 2.50 = m

17.50 = m

20 - 1.25 ( 7 ) = m

20 - 8.75 = m

11.25 = m

20 - 1.25 ( 12 ) = m

20 - 15 = m

5 = m

5 0
3 years ago
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Please help!! With number 1.
zhuklara [117]

I solved this one for someone else yesterday this is what I have.  First find the factor of 1517 1,37,41,1517  So then we need 3 bills   20+20+1=41  1517/41=37 tickets   So each ticket $41

5 0
4 years ago
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