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Alex787 [66]
3 years ago
9

Evaluate a + b for a = 12 and b = 6.

Mathematics
2 answers:
den301095 [7]3 years ago
3 0

Answer:

Here,

a= 12

b = 6

Then,

a+b

= 12 + 6

= 18

.°. 18 is the solution

allsm [11]3 years ago
3 0

Answer:

\boxed{ \bold{ \boxed{ \sf{18}}}}

Step-by-step explanation:

If the values of variables of algebraic expressions are given, the value of the term or expression can easily obtained by replacing the variables with numbers.

Given, a = 12 and b = 6

\sf{a + b}

plug the values

⇒\sf{12 + 6}

Add the numbers

⇒\sf{18}

Hope I helped!

Best regards!!

You might be interested in
Help help help help
Alex

Answer:

<h3>b=\frac{t-5}{4}</h3>

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b<u>+5=t </u>

    -5  -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

<u>4b=t-5</u>

4      4

b= \frac{t-5}{4} \\

This is your answer!

5 0
3 years ago
HELP!!! Anyone know how to solve I know the answer is (-3) but I don’t know how to get there. Thanks!!
Dima020 [189]

Answer:   v = -3

=========================================

Work Shown:

5 = \sqrt{-2-6v}+1\\\\5-1 = \sqrt{-2-6v}\\\\4 = \sqrt{-2-6v}\\\\4^2 = \left(\sqrt{-2-6v}\right)^2 \ \text{ .... square both sides}\\\\16 = -2-6v\\\\16+2 = -6v\\\\18 = -6v\\\\-6v = 18\\\\v = 18 \div (-6)\\\\v = -3

As you can see, we don't square both sides until the square root portion is fully isolated or on its own side. So it happens after we subtract 1 from both sides.

Technically, you are able to square both sides without first isolating the square root. But that would mean you'd have to use the FOIL rule and things would get a bit messier than they have to be. Not to mention that the square root term wouldn't fully go away (so you'd have to square again later down the line).

------------------

Checking the answer:

Replace every copy of v with -3. Simplify both sides. We should end up with the same number on each side

5 = \sqrt{-2-6v}+1\\\\5 = \sqrt{-2-6(-3)}+1\\\\5 = \sqrt{-2+18}+1\\\\5 = \sqrt{16}+1\\\\5 = 4+1\\\\5 = 5\\\\

The answer is confirmed.

4 0
3 years ago
Help please !!!!! i dont know how
dem82 [27]

hello since we are simplifying 15^-3*15^6 all we have to do is add the exponents when we add them we end up with an answer of 15^3

8 0
3 years ago
Find the measure of angle eight in each triangle round each answer to the nearest 10th
vlada-n [284]

Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

  and hypotenuse sides

∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

∴ m∠A = cos^{-1}\frac{5.4}{6}=25.84193

* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

∵ EA = 6.8 ⇒ the hypotenuse

- To find m∠A use the sine function because we have opposite

  and hypotenuse sides

∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

3 0
3 years ago
Which of the following is true for f(x) = 5cos(x) +1?
Helen [10]

Answer:

The range of the function is the set of real numbers -4\leq y\leq6

Step-by-step explanation:

Since the amplitude is 5, this tells us the distance between the midline and the maximum/minimum, where the function oscillates. Here, the minimum is 1-5 = -4 and the maximum is 1+5 = 6. So, the last choice is correct

5 0
2 years ago
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