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3241004551 [841]
2 years ago
7

How many books would need to be purchased from each club for the club's to cost the same

Mathematics
1 answer:
juin [17]2 years ago
4 0
First club 
y= 40 + 10x              y= 40 + 10(8)                =120

Second club 
y= 15x                      y= 15(8)                         =120

now plug a number of the answer choices in each equation until you get the same result for both

The answer is C
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