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3241004551 [841]
3 years ago
7

How many books would need to be purchased from each club for the club's to cost the same

Mathematics
1 answer:
juin [17]3 years ago
4 0
First club 
y= 40 + 10x              y= 40 + 10(8)                =120

Second club 
y= 15x                      y= 15(8)                         =120

now plug a number of the answer choices in each equation until you get the same result for both

The answer is C
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One container holds 1 1/7 quarts of water and second container holds 5 3/4 quarts of water how many more harts of water does the
Anna007 [38]

Answer:

129/28 (4.6 approx.)

Step-by-step explanation:

The first hols 1 1/7 quarts, it is: 1 + 1/7

Using 7 as common denominator and summing:

1 + 1/7 = 7/7 + 1/7 = 8/7

The second holds 5 3/4 which is: 5 + 3/4. Using 4 as common denominator:

5 + 3/4 = 20/4 + 3/4 = 23/4

Now we need to know how much greater is 23/4 than 8/7. For comparing them we need to set them to a common denominator. The easiest way is use a number that is multiple of both, 4 and 7, lets us 28. We need to multiply the numerators by the number that, multiplied by denominators gives us 28. For the first is 4, and for the second 7.

8/7 = (8*4)/7*4=32/28

23/4= (23*7)/4*7 = 161/28

Now, we only have to subtract:

23/4 - 8/7 = 161/28 - 32/28 = 129/28

So, the second container has 129/28 more quarts of water (approx. 4.60) than the first.

3 0
4 years ago
What is the common factor for 9 and 7?
svetoff [14.1K]

Answer:

your answer is 1!

The gcf of 7 and 9 is the largest positive integer that divides the numbers 7 and 9 without a remainder. Spelled out, it is the greatest common factor of 7 and 9. Here you can find the gcf of 7 and 9, along with a total of three methods for computing it. In addition, we have a calculator you should check out. Not only can it determine the gcf of 7 and 9, but also that of three or more integers including seven and nine for example. Keep reading to learn everything about the gcf (7,9) and the terms related to it.

What is the GCF of 7 and 9

If you just want to know what is the greatest common factor of 7 and 9, it is 1. Usually, this is written as

gcf(7,9) = 1

The factors of 9 are 9, 3, 1.

The factors of 7 are 7, 1.

The common factors of 9 and 7 are 1, intersecting the two sets above.

In the intersection factors of 9 ∩ factors of 7 the greatest element is 1.

Therefore, the greatest common factor of 9 and 7 is 1.

8 0
3 years ago
the area of a rectangular wall of a barn is 260 square feet. it's length is 6 feel longer than twice it's width. find the length
scoundrel [369]
L=2w+6
260=lw

Substitute for l
260=w(2w+6)
260= 2w^2+6w
2w^2+6w-260=0
2(w^2+3w-130)
2(w+13)(w-10)
w=-13, w=10

Since width cannot be negative it must be 10
260=l(10)
26=l

Final answer: length-26 ft, width-10ft
6 0
3 years ago
102/159 = x/4<br><br> Find X
-BARSIC- [3]
102/159 = x/4
34/53 = x/4
34(4) = x(53)
136 = 53x
136/53 = x
5 0
3 years ago
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]​
Alekssandra [29.7K]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
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