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madreJ [45]
3 years ago
14

Three percent converted to a decimal

Mathematics
2 answers:
liberstina [14]3 years ago
6 0
p\%=\dfrac{p}{100}\\\\3\%=\dfrac{3}{100}=3:100=0.03
Ymorist [56]3 years ago
5 0
The answer is 0.03. Hope I help:)
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I have a riddle for you I have 31 82,400,060 tens and 100 hundreds
klasskru [66]

Answer: 31824010600

Step-by-step explanation: 3182400060 tens and 100 hundreds = 31824010600.

7 0
3 years ago
Pleaseee help if you can!!!!!!!
REY [17]

Answer:

85 degrees

Step-by-step explanation:

Theses angles are the same because its parallell

3 0
2 years ago
2y+8×=2 identify the table that would correctly graph this equation
lys-0071 [83]

We have

2y+8x=2

In order to obtain easily the table, we need to clear y

\begin{gathered} 2y=-8x+2 \\ y=\frac{-8x+2}{2} \\ y=-4x+1 \end{gathered}

then we evaluate for values of x

if x=0

y=-4(0)+1=1

y=1

if x=1

y=-4(1)+1=-3

y=3

if x=2

y=-4(2)+1=-7

y=-7

if x=3

y=-4(3)+1=-11

y=-11

So the table for the given equation is

x y

0 1

1 -3

2 -7

3 -11

3 0
1 year ago
Giving BRAINLIEST for correct awnser! Factor the expression below.
melomori [17]

Answer:

C. 6a + 5b

Step-by-step explanation:

36a^2-25b^2

Rewriting as

(6a)^2 - (5b)^2

We know this is the difference of squares

(x^2 -y^2) = (x-y)(x+y)

(6a - 5b) (6a+5b)

6 0
3 years ago
Read 2 more answers
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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