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Delvig [45]
3 years ago
12

PLS HELP ILL GIVE BRAINLIEST

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer: Think of it this way, symmetry is basically a mirror and you can better find the perimeter because you'll know that the sides are the same length

Step-by-step explanation:

Well if you have two sides that are symmetrical or an entire shape is symmetrical you can find the perimeter easier. So let's say two lines are symmetrical and one has the length of 2 the other one can also be two. If we have a symmetrical shape, then is would be a complete reflection.

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An inscribed angle that opens to a diameter has an intersected arc that is a ________________. The angle is a ______ angle becau
kherson [118]

Answer:

An inscribed angle that opens to a diameter has an intersected arc that is 180 degrees. The inscribed angle is a right angle (90 degrees) because

\frac{1}{2}(180^o)=90^o

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc comprising

Remember that

The diameter divide the circle into two equal parts

so

An inscribed angle that opens to a diameter has an intersected arc that is 180 degrees

The inscribed angle is 90 degrees because

\frac{1}{2}(180^o)=90^o

therefore

An inscribed angle that opens to a diameter has an intersected arc that is 180 degrees. The inscribed angle is a right angle (90 degrees) because

\frac{1}{2}(180^o)=90^o

3 0
3 years ago
Given: MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm Find: The midsegment of MNOK. Need help now will give 15 points
Anastaziya [24]

Answer:  24 unit

Step-by-step explanation:

Here,  MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm

Since, a mid segment is the line segment which joins the mid points of the equal sides of the isosceles trapezoid.

Let LO is the mid segment of trapezoid  MNOK

Where, Let J is the intersection point of KN and LO.

Therefore, LO= LJ+JO --------(1)

And, KL=LO , MO=ON

Since, In triangle KLJ,

∠LKJ=90° ( given),  ∠KLJ=60° ( because, LO║ON and it is given m∠M=60°)

Thus, ∠KJL=30°

Therefore, sin 30°=LK/LJ=8/LJ ( Because ΔMKN is a isoceleus triangle where ∠MKN=∠MNK=30°⇒KM=MN)

⇒LJ=8×2=16

Now, In ΔNOJ,

∠ONJ=∠OJN=30°

Therefore, ON=OJ ( by the property of isosceles triangle)

⇒OJ=8

Thus, By putting these values in equation 1) we get,

LO=16+8=24 cm



7 0
4 years ago
Write the equation of the line that is perpendicular to 5x + 3y = -21 and
Marta_Voda [28]

Answer:

5x + 3y = -21

Step-by-step explanation:

i think sorry if its wrong

3 0
2 years ago
For the following normal distribution, give the x-values of the inflection points of the curve (the points where the curve's con
3241004551 [841]

Answer:

The x-values of the inflection points of the curve are x = -52 and x = 52.

Step-by-step explanation:

Suppose we have a normal curve with mean \mu and standard deviation \sigma

The x-values of the inflection points of the curve are x = \mu - \sigma and x = \mu + \sigma

x ~ N(0, 52)

This means that \mu = 0, \sigma = 52

So

x = 0 - 52 = -52

x = 0 + 52 = 52

The x-values of the inflection points of the curve are x = -52 and x = 52.

6 0
3 years ago
The radius of a circular rug is 30 inches. What is the approximate circumference, in inches, of this rug?
AleksandrR [38]

Answer:

Step-by-step explanation:

You need to use the formula 2 x pi x r so it would be 60 x pi which equals 188.5 inches

6 0
3 years ago
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