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2 years ago

Triangle and triangle are similar. What is the measure of side ?

Mathematics

2 answers:

snow_lady [41]2 years ago

8 0

When two triangles are similar, they're sides are in proportion.

In order to find the unknown side, we first have to find the ratio of the larger triangle to the smaller triangle.

We can use the sides TV and LN to make the proportion.

$\frac{LN}{TV}$ = $\frac{21}{6}$

The ratio between the two triangles is 21:6

Now we can solve for the unknown side.

$\frac{21}{6}$ = $\frac{LM}{8}$

Cross multiply:

8 * 21 = 6 * LM

168 = 6LM

Divide both sides by 6:

LM = 28

The unknown side's length is 28 centimeters

Good luck!

Artyom0805 [142]2 years ago

3 0

Answer:

28cm is the measurement

Step-by-step explanation:

The TU side is 1/4 longer than the TV side.

So if you apply this rule to the LMN triangle:

7x4=28cm.

Hope this helps ;-))

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Which four inequalities can be used to find the solution to this absolute value inequality?

natita [175]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

This gives:

x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

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6 0

2 years ago

10 points, doing this one again because I got a wrong answer last time but regardless thank you for trying to help

Alik [6]

Hey ! there

Answer:

Value of missing side i.e. TE is 12 feet

Step-by-step explanation:

In this question we are provided with a right angle triangle having TS - 35 ft and SE - 37 ft . And we are asked to find the missing side that is TE using Pythagorean Theorem .

Pythagorean Theorem : -

According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.

H² = P² + B²

Where ,

H refers to Hypotenuse

P refers to Perpendicular

B refers to Base

Solution : -

In the given triangle ,

Base = TE

Perpendicular = TS ( 35 feet )

Hypotenuse = SE ( 37 feet )

Now applying Pythagorean Theorem :

$\quad \longmapsto \qquad \:SE {}^{2} = TS {}^{2} + TE {}^{2}$

Substituting values :

$\quad \longmapsto \qquad \:37 {}^{2} = 35 {}^{2} + TE {}^{2}$

Simplifying it ,

$\quad \longmapsto \qquad \:1369 = 1225 + TE {}^{2}$

Subtracting 1225 on both sides :

$\quad \longmapsto \qquad \:1369 - 1225 = \cancel{1225} + TE {}^{2} - \cancel{1225}$

We get ,

$\quad \longmapsto \qquad \:144 = TE {}^{2}$

Applying square root to both sides :

$\quad \longmapsto \qquad \ \sqrt{ 144} = \sqrt{TE {}^{2}}$

We get ,

$\quad \longmapsto \qquad \: \red{\underline{\boxed{\frak{TE = 12 \: feet}}}} \quad \bigstar$

Henceforth , value of missing side is 12 feet .

Verifying : -

Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,

SE² = TS² + TE²

Substituting value of SE , TS and TE :

37² = 35² + 12²

1369 = 1225 + 144

1369 = 1369

L.H.S = R.H.S

Hence , Verified .

Therefore , our answer is correct .

<h2>#Keep Learning</h2>

6 0

2 years ago

Read 2 more answers

Pls help I’m so confused

solniwko [45]

Answer:

Yes

Step-by-step explanation:

First, look for the hypotenuse (diagonal) of the base of the box. We have the two legs: 13 inches and 35 inches.

Set up an equation using the Pythagorean theorem:

$13^2+35^2=C^2$

Solve for C:

169 + 1225 = C^2

1394 = C^2

C ≈ 37.34

Now that we have the diagonal of the base, we know can move on to find the value of the interior diagonal. We have two legs: 13 inches and 37.34 inches.

Again, set up an equation using the Pythagorean theorem, and solve for the new C:

$13^2+37.34^2=C^2$

1563.2756 = C^2

C = 39.54

The interior diagonal of the box is approximately 39.54 inches long, which is longer than Kylie's baton, which is 38 inches long. So, she can fit the baton in the box.

Have a nice day! :)

7 0

3 years ago

Write 360 as a product of prime factors. Give your answer in index form.

WINSTONCH [101]

The answer to the question of what I did do not mean that to me I was just saying

3 0

2 years ago

Read 2 more answers

Listed below are the lead concentrations in mu ??g/g measured in different traditional medicines. Use a 0.10 0.10 significance l

laiz [17]

Answer:

We conclude that the mean lead concentration for all such medicines is less than 17 mu.

Step-by-step explanation:

We are given below are the lead concentrations in mu;

6.5 18.5 21.5 5.5 8.5 4.5 4.5 17.5 15.5 20

We have to test the claim that the mean lead concentration for all such medicines is less than 17 mu.

Let $\mu$ = mean lead concentration for all such medicines.

So, Null Hypothesis, $H_0$ : $\mu$ = 17 mu {means that mean lead concentration for all such medicines is equal to 17 mu}

Alternate Hypothesis, $H_A$ : $\mu$ < 17 mu {means that the mean lead concentration for all such medicines is less than 17 mu}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean lead concentration = $\frac{\sum X}{n}$ = 12.25 mu

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 6.96 mu

n = sample size = 10

So, test statistics = $\frac{12.25 -17}{\frac{6.96}{\sqrt{10}}}$ ~ $t_9$

= -2.16

The value of t test statistics is -2.16.

Now, the P-value of the test statistics is given by the following formula;

P-value = P( $t_9$ < -2.16) = 0.031

Now, at 0.10 significance level the t table gives critical value of -1.383 for left-tailed test. Since our test statistics is less than the critical value of t as -2.16 < -1.383, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean lead concentration for all such medicines is less than 17 mu.

7 0

3 years ago