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vampirchik [111]
3 years ago
5

IXL Q.12 PLS HELP I HAVE BEEN STUCK ON THIS ONE FOR SOME TIME.

Mathematics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

m∠1 = 100°

Step-by-step explanation:

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Elaine has 1 gallon of paint. She is going to pour it into a paint tray that measures 10 in wide 12 in long and 5 cm deep. ( 1 g
padilas [110]

Answer:

b. The paint will not fill the tray by 5.22 in3.

Step-by-step explanation:

The computation is shown below:

First we have to determine the volume of tray by using the following equation

V = L \times W \times H

Now transform this from dimensions to inches

Now  putting the values,

V = 10\times12\times (5\times(\frac{1}{2.54})) \\\\As\ 5 cm = 5 \times (\frac{1}{2.54})

the volume would be equivalent to the

236.22 inches^3

Now 1 gallon is 231 inches^3

So, the remaining would be

= 236.22 - 231

= 5.22^3

Therefore the correct option is b.

Hence, all the other options are wrong

7 0
3 years ago
Which of the following are solutions for x<br> in the equation ax2 = bx?<br> Select all that apply.
Brums [2.3K]
I uploaded it here as the answers Bc




Slkwowkneojw
5 0
2 years ago
Write the equation of a line in slope-intercept form that goes through the points
Stella [2.4K]

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

5 0
2 years ago
Expand 4(z+6) into the simplest form.
Ratling [72]
4z + 24 is the answer
4 0
2 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
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