Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
I could say that they will give you different answers since they are the same numbers and are in the same order but are paired differently
Answer:
(2a, b )
Step-by-step explanation:
Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ 
(x₁ + x₂ ), (y₁ + y₂ ) ]
Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus
midpoint = [ (2a + 2a), (2b + 0 ) ] = (2a, b )
You have to put the number under 1 so you would get 1 over -27
Answer:
0.26 and 0.577
Step-by-step explanation:
Given :
x :___0 ___ 1 ____ 2 ____ 3
f(x):_0.80 _0.15__0.04 __0.01
The mean :
E(X) = Σ(x * p(x))
E(X) = (0*0.8) + (1*0.15) + (2*0.04) + (3*0.01)
E(X) = 0 + 0.15 + 0.08 + 0.03
E(X) = 0.26
Var(X) = Σx²*p(x)) - E(x)²
Σx²*p(x)) = (0^2*0.8) + (1^2*0.15) + (2^2*0.04) + (3^2*0.01) = 0.4
Σx²*p(x)) - E(x)² = 0.4 - 0.26² = 0.3324
Std(X) = √0.334 = 0.577
