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blondinia [14]
4 years ago
10

Can 57 rows be divided into equal sections

Mathematics
2 answers:
Serjik [45]4 years ago
8 0
Yes it can be divided into 3 equal sections of 19
Anna71 [15]4 years ago
7 0
Hello there, and thank you for asking your question here on brainly.

It cannot be divided into equal sections because it is an odd number.

You can find that out by dividing it by even numbers, they'll all be decimals.

Hope this helped!! ☺♥
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1a simplify 6x × 3y​
lesantik [10]
18xy
You need to do 6*3=18
Then x*y= xy
6 0
3 years ago
A sample of 1700 computer chips revealed that 51% of the chips do not fail in the first 1000 hours of their use. The company's p
hichkok12 [17]

Answer:

The answer is -1.2

Step-by-step explanation:

Recalling the standard deviation formula,

we have : σ = sqrt[ P * ( 1 - P ) / n ]

Where sqrt = square root

n = Number of derivative

Therefore,:

if, H0: p is not 48%  vs H1: p1 = 48%

 

 

standard deviation is:

σ = sqrt[ P * ( 1 - P ) / n ] = sqrt[ .48*.49/900 ] = .01666333+ z -score is (p-P)/σ

= (.51-.53)/.01666333

The answer therefore =  -1.2

 ICONCLUSION:

It can therefore be concluded that there is statistical evidence that the proportions are different. H0 accepted in the hypothesis.

3 0
4 years ago
Read 2 more answers
Mary used 14 meters of ribbon to make bows and strips. she used 3/4 as much ribbon for bows as she did for strips. how many mete
podryga [215]
Total = 14 m.
ratio of bows:strips = 3:4
Length for bows = 3/(3+4)*14=6 m
Length for strips = 4/(3+4)*14=8 m

Check: 6m + 8m = 14 m = total, ok.
5 0
3 years ago
Read 2 more answers
The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th
ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

z=\frac{x-\mu}{\sigma}

z=\frac{38-38}{6}=\frac{0}{6}=0

Now we will find z-score corresponding to 56.

z=\frac{56-38}{6}=\frac{18}{6}=3

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is -3\sigma\text{ to }3\sigma.

We can see that data point 38 is at mean as it's z-score is 0 and z-score of 56 is 3. This means that 56 is 3 standard deviation above mean.

We know that mean is at center of normal distribution curve. So to find percentage of data points 3 SD above mean, we will divide 99.7% by 2.

\frac{99.7\%}{2}=49.85\%

Therefore, approximately 49.85\% of lightbulb replacement requests numbering between 38 and 56.

6 0
4 years ago
Today only, a sofa is being sold at a 32% discount. The sale price is $493.
Naddik [55]

Answer:

yesterday the price was. $650.76

8 0
3 years ago
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