Total distance 5 km; at 5km / 0.65 h =
Second part distance: x; at 6 km/h, during t2
First part distance: 5 - x; at 8.75 km/h, during t1
V = d/t ⇒ t = d/V
t2 = x/6
t1=[5-x]/8.75
t2 + t1 = 0.65
x/6 + [5-x]/8.75 = 0.65
x/6 + 5/8.75 - x/8.75 = 13/20
x/6 - x/8.75 = 13/20 - 5/8.75
x/6 - 4x/35 =13/20 - 20/35
35x - 24x = (35*6)(35*13 - 20*20)/(20*35)
11 x = 16.5
x = 16.5/11 = 1.5 km
Answer:
last oneeee
Step-by-step explanation:
Answer:
Step-by-step explanation:
-The locust population grows by a factor and can therefore be modeled by an exponential function of the form:
Where:
is the population after t days.
is the initial population given as 7600
is the rate of growth
is time in days
-Given that the growth is by a factor of 5( equivalent to 500%), the r value will be 5
-The population increases by a factor of 5 every 22 days. therefore at any time instance, t will be divided by 22 to get the effective time for calculations.
Hence, the exponential growth function will be expressed as:
The Answers is
g(x) = (x + 1)/(x - 2)
h(x) = 4 - x
g(h(x)) = (4 - x + 1)/(4 - x - 2) = (5 - x)/(2 - x)
g(h(-3)) = (5 - (-3))/(2 - (-3)) = (5 + 3)/(2 + 3) = 8/5
g(h(-3)) = 8/5.
The y-intercept is 3...when plottibg this plot 3 first then use -8x (-8/1) as your slope form your y-intercept going both directions.
