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grandymaker [24]
3 years ago
8

1 3.1.5 Quiz: Comparing Functions

Mathematics
1 answer:
Burka [1]3 years ago
7 0

Answer:

the statements are not written here .

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Calculate the number of acres required to produce 1,000 gallons of oil in one year from microalgae and soybeans. Which one (micr
Inessa05 [86]

Answer:

microalgae required less space.

Step-by-step explanation:

Amount of oil to be produced = 1,000 gallons

Now,

We know

10,000 gallons of oil is extracted from the miroalgae per acre per year

and,

From soyabeans the oil extracted = 50 gallons per acre per year

therefore,

To produce 1,000 gallons number of acres required by microalgae

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from microalgae]

= 1,000 ÷ 10,000

= 0.1 acres

similarly

To produce 1,000 gallons number of acres required by soyabeans

= [ Amount of oil to be produced ] ÷ [ oil extracted per acre from soyabeans]

= 1,000 ÷ 50

= 20 acres

hence,

microalgae required less space.

7 0
3 years ago
The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages
Ivanshal [37]
Lionel had 250 pages copied

This is because 20/.08=250.
8 0
4 years ago
Read 2 more answers
What is the product of? (7x^2)(2x^3+5)(x^2-4x-9)
pav-90 [236]
(7x^{2})(2x^{3} +5)( x^{2} -4x-9)

(14 x^{5} +35 x^{2})( x^{2} -4x-9)
=14 x^{7} -56 x^{6}-126 x^{5}+35 x^{4}-140 x^{3}-315 x^{2}
6 0
3 years ago
Read 2 more answers
What is the surface area of this net?
balandron [24]

Answer:

It is 27.4

Step-by-step explanation:

First you need to find the area of the three rectangle.

Area=base*high

You do 4*2 for about 3 times

Which is 8 for 4*2

Then you multiply it 3 more time and get 24.

After that you add 24+1.7+1.7 and get 27.4

4 0
3 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
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