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Soloha48 [4]
3 years ago
10

How many one-tenths are in two-fifths?

Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0

Answer:

4

Step-by-step explanation:

2/5

=4/10/1/10

=4

if my answer helps please mark as brainliest.

lorasvet [3.4K]3 years ago
5 0
2/5 one-tenths are in two-fifths... trust me it took me 10 mins to do this
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Megan is deciding when she needs to leave for school. If it typically takes her 15 minutes to walk to school, which is a reasona
Andreas93 [3]

Answer:

A) between 7:40 and 7:45

Step-by-step explanation:

Given,

The maximum time taken by her to walk to school = 15 minutes,

Since, the school starts on 8:00 AM,

Also, 15 minutes before 8:00 AM = 7:45 AM,

Thus, the maximum time at which she has to leave home = 7: 45 AM,

Hence, the reasonable estimate of the time she should leave home to get to school by 8:00 is between 7:40 and 7:45.

OPTION A would be correct.

3 0
3 years ago
What is YZ?<br><br> Enter your answer as a decimal in the box.
maks197457 [2]

Answer:

YZ = 18.4 in

Step-by-step explanation:

The midsegment YZ is half the length of the third side VX , then

YZ = \frac{1}{2} × 36.4 = 18.2

8 0
3 years ago
Read 2 more answers
I give you brainless if you get it right
SSSSS [86.1K]
<h2><u>79 degrees</u> is the correct answer!</h2><h3></h3><h3>Line PU is <u>supplementary.</u></h3><h3>30 + 34 + 37 = 101</h3><h3>180 - 101 = <u>79</u></h3><h3><u /></h3><h3>I want to be marked "brainless."</h3><h3>I want to be a zombie.</h3><h3>lm-ao</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3>
5 0
3 years ago
Use the Pythagorean theorem to obtain the function​ D(x) for the length of the diagonal of a double square of width x.
Yuri [45]

Answer:

D(x)= x\sqrt{2}

Step-by-step explanation:

Given

Side = x

Required

Represent the diagonal as a function

Using Pythagoras theorem, the diagonal is:

D^2= Side^2 + Side^2

Substitute x for Side

D^2= x^2 + x^2

D^2= 2x^2

Take the square root of both sides

D= \sqrt{2x^2

Split

D= \sqrt{2} * \sqrt{x^2

D= \sqrt{2} * x

D= x\sqrt{2}

Express as a function.

D(x)= x\sqrt{2}

4 0
3 years ago
What function is increasing? will give brainlist !
Wewaii [24]

Answer:

Option B.

Step-by-step explanation:

Option A.

f(x) = (0.5)^{x}

Derivative of the given function,

f'(x) = \frac{d}{dx}(0.5)^x

      = (0.5)^x[\text{ln}(0.5)]

      = -(0.693)(0.5)^{x}

Since derivative of the function is negative, the given function is decreasing.

Option B. f(x) = 5^x

f'(x) = \frac{d}{dx}(5)^x

      = (5)^x[\text{ln}(5)]

      = 1.609(5)^x

Since derivative is positive, given function is increasing.

Option C. f(x) = (\frac{1}{5})^x

f'(x) = \frac{d}{dx}(\frac{1}{5})^x

      = \frac{d}{dx}(5)^{(-x)}

      = -5^{-x}.\text{ln}(5)

Since derivative is negative, given function is decreasing.

Option D. f(x) = (\frac{1}{15})^x

                f'(x) = -15^{-x}[\text{ln}(15)]

                       = -2.708(15)^{-x}

Since derivative is negative, given function is decreasing.

Option (B) is the answer.

7 0
3 years ago
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