Answer:
x= 5/4 + −1/4√17 or x = 5/4 + 1/4√17
Step-by-step explanation:
Answer:
b. 0.02
Step-by-step explanation:
The smaller the p-value, the stronger the evidence that you should reject the null hypothesis. In this case, this will mean rejecting that the proportions are not significantly different.
Usually, a p-value is considered to be statistically significant when p ≤ 0.05.
From the answer options provided, alternative b. 0.02 is the only one that represents the difference in proportions to be statistically significant (there is only a 2% chance that the proportions are not significantly different).
Therefore, the answer is b. 0.02
Answer:
NOT 100% sure! If its not this I think its 
8(-1/4)-(3)2-3=-2-6-3=-11
Answer:
a) 17.5
b) 15.6
c) 13.3
d) 21.51
Step-by-step explanation:
The given function is equal to:
f(x)=kx^2
where

where y=23
Clearing k=0.00025
a) 
b)
c) The function is equal to:
f(x)=k(1+2x)

where y=20
k=0.0024

d) 