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Margaret [11]
3 years ago
12

Mitchel owns a livestock trailer that can hold a maximum of 5,000 pounds. The average weight of each goat is 90 pounds, and the

average weight of each calf is 360 pounds. Mitchel would like to know how many goats and calves he can transport in a single trip.
The inequality that represents this situation is graphed here.

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

The number of cows and calves Mitchel can transport is determined by the inequity 90g+360c \leq 5000

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Helpppp ASAP<br> Drag Values To complete each equation
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Given:

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Part B: \left(17^{6}\right)^{3} \cdot 17^{-9}

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Solution:

Part A:

Using exponent rule: (a^m)^n=a^{mn}

$\frac{\left(17^{3}\right)^{6} \cdot 17^{-10}}{17^{8}}=\frac{\left(17\right)^{3\times   6} \cdot 17^{-10}}{17^{8}}

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Using exponent rule: a^m \cdot a^{n}= a^{m+n}

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Cancel the common factor, we get

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Part B:

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Using exponent rule: (a^m)^n=a^{mn}

\left(17^{6}\right)^{3} \cdot 17^{-9}=\left(17\right)^{6\times 3} \cdot 17^{-9}

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Using exponent rule: a^m \cdot a^{n}= a^{m+n}

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Step-by-step explanation:

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