Question

Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarterof the time and the unit cost of electricity is $0.09/kWh, the electricity cost of this refrigerator per month (30 days) is(a) $3.56 (b) 55.18 (a 53.54 {0159.26 [6) $20.74

Answer 1

Answer:

$5.184

Explanation:

The cost can be calculated using the formula: $Cost = Load \ factor \times Number \ of \ hours \ \\M_{month} = M_{units} \times W$

Before using this, we require the following conversions:

320 W → kW:

$\frac {320}{1000} = 0.32$

30 Days → Hours:

$30 \times 24 = 720$

Using the above stated formula:

$M_{month} = 0.09 \times 0.32 \times \frac{1}{4} \times 720 = 5.184$