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Gnom [1K]
3 years ago
9

How should employees talk to clients)

Engineering
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

Explanation:

Respectfully and calmly

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If a heat engine has an efficiency of 30% and its power output is 600 W, what is the rate of heat input from the combustion phas
jarptica [38.1K]

Answer:

The heat input from the combustion phase is 2000 watts.

Explanation:

The energy efficiency of the heat engine (\eta), no unit, is defined by this formula:

\eta = \frac{\dot W}{\dot Q} (1)

Where:

\dot Q - Heat input, in watts.

\dot W - Power output, in watts.

If we know that \dot W = 600\,W and \eta = 0.3, then the heat input from the combustion phase is:

\eta = \frac{\dot W}{\dot Q}

\dot Q = \frac{\dot W}{\eta}

\dot Q = \frac{600\,W}{0.3}

\dot Q = 2000\,W

The heat input from the combustion phase is 2000 watts.

8 0
2 years ago
I want a problems and there solutions of The inception of cavitation?​
Ugo [173]

Answer:

The overview of the given scenario is explained in explanation segment below.

Explanation:

  • The inception of cavitation, that further sets the restriction for high-pressure and high-free operation, has always been the matter of substantial experimental study over the last few generations.
  • Cavitation inception would be expected to vary on the segment where the local "PL" pressure mostly on segment keeps falling to that are below the "Pv" vapor pressure of the fluid and therefore could be anticipated from either the apportionment of the pressure.

    ⇒  A cavitation number is denoted by "σ" .

4 0
3 years ago
While discussing the testing of a Hall-effect switch:
sergejj [24]

Answer:

your answer is technician A

6 0
2 years ago
Dean is buying a home for $170,000. The mortgage company he decided to use to finance the home requires a 10% down payment. What
ANTONII [103]
They answer is 3. $17,00
8 0
3 years ago
Read 2 more answers
A tensile specimen with a 12mm initial diameter and 50mm gage length reaches maximum load at 90KN and fractures at 70KN
Aleksandr-060686 [28]

Answer:

i) 796.18 N/mm^2

ii) 1111.11 N/mm^2

Explanation:

Initial diameter ( D ) = 12 mm

Gage Length = 50 mm

maximum load ( P ) = 90 KN

Fractures at =  70 KN

minimum diameter at fracture = 10mm

<u>Calculate the engineering stress at Maximum load and the True fracture stress</u>

<em>i) Engineering stress at maximum load = P/ A </em>

= P / \pi  \frac{D^2}{4}  = 90 * 10^3 / ( 3.14 * 12^2 ) / 4

= 90,000 / 113.04 = 796.18 N/mm^2

<em>ii) True Fracture stress =  P/A </em>

= 90 * 10^3 / ( 3.24 * 10^2) / 4

= 90000 / 81  =  1111.11 N/mm^2

3 0
2 years ago
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