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tamaranim1 [39]
3 years ago
6

ABC Lumber Company has stock with these probabilities of value after five years with an initial investment of $2,000: 55% probab

ility of a $1,800
value, 20% probability of a $2,100 value, and 25% probability of a $2.700 value. What is the expected value of the investment after five years?
A
$2,085
B. $2,000
C. $1,950
D. $1,545
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

Step-by-step explanation:

c is the answer

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lisabon 2012 [21]
It's 6!

When you multiply both the numerator and denominator by the same number, you will have an equivalent to the fraction you started with because the new fraction can be reduced to the original fraction.

2/3 = 4/6 = 6/9 = 8/12 = 10/15 = 12/15 etc.
4 0
3 years ago
What is 5x+7y+8z-2x+3y+5-z
DochEvi [55]
5x+7y+8z-2x+3y+5-z = 3x+10y+7z+5
4 0
4 years ago
Three hundred is 6 percent of what number
faust18 [17]
300 / 0.06 = 5000

answer <span>Three hundred is 6 percent of 5,000

</span>
8 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(
VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

(x^{2} )^4= x^{2(4)} = x^8

(x^4)^3 = x^{4(3)} = x^{12}


When you divide an exponent by an exponent, you subtract the exponents

For example:

\frac{x^4}{x^1} =x^{4-1}=x^3


When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

x^{-3}=\frac{1}{x^3}

\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5



\frac{(3a^2b)^3}{9(ab)^4}

You can think of it like this if you want:

\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}  Now multiply the outside exponents into the exponents in the parentheses

\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)} Divide 27 and 9

\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}



Your answer is \frac{3a^2}{b}



5 0
3 years ago
what are the domain of the function what are the domain of the function y equal 2 start root 3x plus 4 end root?
inna [77]
Y=sqrt(3x+4)

3x+4 must be positive

3x+4>=0
Solving for x:
3x+4-4>=0-4
3x>=-4
3x/3>=(-4)/3
x>=-(4/3)

Domain of the function = [-(4/3), +Infinite)
5 0
4 years ago
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