<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
Answer:
Following are the solution to the given question.
Step-by-step explanation:
Please find the graph file and its solution in the attachment.
Similarly:
For point 1:
For point 2:
For point 3:
For point 4:
For point 5:
Convert each mixed number to an improper fraction
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Convert 6&1/2 to an improper fraction
6&1/2 = (6*2+1)/2
6&1/2 = (12+1)/2
6&1/2 = 13/2
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Do the same for 9&1/4
9&1/4 = (9*4+1)/4
9&1/4 = (36+1)/4
9&1/4 = 37/4
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Now multiply the improper fractions 13/2 and 37/4. Multiply straight across
(13/2)*(37/4) = (13*37)/(2*4)
(13/2)*(37/4) = 481/8
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The last step is to use long division to find the mixed number equivalent of 481/8
Or we an say
60*8 = 480
So 60*8+1 = 480+1
which means
481/8 = (480+1)/8 = 480/8+1/8 = 60&1/8
Making the final answer to be choice C
Another way to get the answer is to convert 481/8 into a decimal to get 60.125 and then convert that back to a mixed number. You should get 60&1/8
