All categories

4 years ago

Find the specified element in the inverse of the given matrix

1 answer:

6 0

What is the given matrix?
you didn't show a matrix.
the components of the matrix are the elements.
and the elements of the inverse matrix are the elements of the inverse matrix
1)
so if matrix A is 1 4 1
2 5 2
3 6 3
2)
14114
25225
36336

3)
15 24 12
15 12 24
4)
[A]=(15+24+12=51)-(15+12+24=51)
[A]=0
5)
  52 23 25
63 23 36

41 11 14
63 33 36

41 12 14
52 12 25
6)

15-12 6-6 12-15

12-6 3-3 6-12

8-5   2-2 5-8

7)
3 0   -3

6 0 -6

3 0 -3
8)
(+)3 (-)0 (+)-3

(-)6 (+)0 (-)-6

(+)3 (-)0 (+)-3
=

  3 0 -3
-6 0   6
3 0 -3

9)
  3 -6 3
N= 0 0 0
-3 6 -3
10) the inverse of [A]= 1/|A|*[N]
which is in this case ⁻A= 0
because |A|=0

You might be interested in

How does the graph of f(x) =-3^2x-4 differ from the graph of g(x)=-3^2x

Neko [114]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
~~~~y={{ A}}({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)={{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\\\
f(x)={{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
~~~~~~if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
~~~~~~if\ {{ D}}\textit{ is negative, downwards}\\\\
~~~~~~if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's check,

$\bf f(x)=-3^{\stackrel{B}{2}x\stackrel{C}{-4}}\qquad \qquad g(x)=-3^{2x}\implies g(x)=-3^{\stackrel{B}{2}x\stackrel{C}{+0}}$

notice, g(x) has a horizontal shift of C/B or +0/2, or just 0, none.

while f(x) has a horizontal shift of C/B or -4/2, or -2, to the right.

so f(x) is really just g(x), but shifted horizontally over 2 units to the right.

3 0

3 years ago

each unit square of a 3-by-3 unit-square grid is to be colored either blue or red. for each square, either color is equally like

makkiz [27]

The probability of obtaining a grid that does not have a 2-by-2 red square 16 2/3%

probability : The probability of an event can be calculated by means of probability formula via honestly dividing the favorable quantity of outcomes by way of the total variety of viable consequences.

<u>Step-by using-step clarification:</u>

<u>given that:</u>

form are both square or circle with both equally likely :

for this reason,

P(square) = half of ; P(circle) = half of

color are either blue, pink or inexperienced with the 3 equally likely ;

P(purple) = 1/3 ; P(green) = 1/three ; P(blue) = 1/three

chance of creating a inexperienced circle :

independent probability

P(green n circle) = p(inexperienced) * p(circle)

P(green n circle) = 1/3 * half of

P(green n circle) = 1/6

= 0.16666

(0.16666 * 100%) = 16.6666%

= 16 2/3%

To learn more about probability Visit : brainly.com/question/18920335

#SPJ4

3 0

2 years ago

Solve 82×41 , show ur work !

lidiya [134]

82
*41

2*1=2
8*1=8
4*2=8
8*4=32
328+82=410

4 0

3 years ago

Expand 6(x-8)= x- (8) = help me

maksim [4K]

Answer:

x = 8

Step-by-step explanation:

6(x-8)= x- (8)

6x - 48=x - 8

6x- 48 + 48 = x - 8 + 48

6x = x + 40

6x - x = x + 40 - x

5x = 40

5x/5 = 40/5

x = 8

Hope it helps! :)

3 0

3 years ago

Answer this please it’s for algebra 2

Sergeu [11.5K]

Part a)

P(junior) = (number of juniors)/(number total)

P(junior) = 235/705

P(junior) = 1/3 exactly

P(junior) = 0.33333 approximately

======================================

Part b)

P(freshman and LG) = (number of freshman who have LG)/(number total)

P(freshman and LG) = 70/705

P(freshman and LG) = 14/141 exactly

P(freshman and LG) = 0.09929 approximately

======================================

Part c)

n(junior) = number of juniors = 235

n(samsung) = number of people who have samsung = 274

n(junior and samsung) = number of juniors who have samsung = 93

----

n(junior or samsung) = n(junior)+n(samsung)-n(junior and samsung)

n(junior or samsung) = 235+274-93

n(junior or samsung) = 416

----

P(junior or samsung) = n(junior or samsung)/n(total)

P(junior or samsung) = 416/705 exactly

P(junior or samsung) = 0.59007 approximately

======================================

Part d)

n(sophomore and apple) = number of sophomores who have apple

n(sophomore and apple) = 80

n(apple) = number of students who have apple

n(apple) = 261

P(sophomore | apple) = n(sophomore and apple)/n(apple)

P(sophomore | apple) = 80/261 exactly

P(sophomore | apple) = 0.30651 approximately

======================================

Part e)

define the events

A = junior who has apple

B = junior who has samsung

C = person is a junior

n(A or B) = number of juniors who have apple or samsung

n(A or B) = n(A) + n(B) ... A and B assumed mutually exclusive

n(A or B) = 87+93

n(A or B) = 180

n(C) = 235

P( (Apple or Samsung) | Junior ) = n(A or B)/n(C)

P( (Apple or Samsung) | Junior ) = 180/235

P( (Apple or Samsung) | Junior ) = 36/47 exactly

P( (Apple or Samsung) | Junior ) = 0.76596 approximately

4 0

4 years ago