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The probability of at least three heads can be found by<span><span>∑<span>k=3</span>4</span><span>(<span>4k</span>)</span><span>.5k</span><span>.5<span>4−k</span></span>=<span>516</span></span></span>
Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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Answer:
( x - 1) ( 2x + 3)
Step-by-step explanation:
It's actually the other way round.
2x^2- + x - 3
( 2x^2 - 2x) + (3x-3)
2x ( x-1 ) + 3( x-1)
( x - 1)(2x+3)
Its the other way around
HOPE IT HELPED
Answer:
A.
Step-by-step explanation:
yan na yannnnnnnnnnnnnnnn
Supplementary angles definition: They add up to 180°
There are several ways to prove a parallelogram:
1. Opposite sides theorem converse
2. Opposite angles theorem converse
3. Parallelogram diagonals theorem converse
4. Parallel congruent sides theorem
∠P + ∠Q = 180° --1
∠P + ∠S = 180° --2
1: ∠P = 180° - ∠Q
Sub 1 into 2:
180° - ∠Q + ∠S = 180°
180° + ∠S = 180° + ∠Q
∠S = ∠Q
Or you can try saying the opposite sides are parallel, since they are interior angles and those are straight lines
