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3 years ago

When the result of an expression is assigned to a temporary memory location, what is the size of memory allocated?

Computers and Technology

1 answer:

MAXImum [283]3 years ago

4 0

Answer:

Default size is allocated dynamically

Explanation:

Dynamic memory allocation refers to managing system memory at runtime.

Dynamic memory allocation uses the heap space of the system memory.

When the result of an expression in a code, such as C++, is assigned to a computer's temporary memory location, the default size of the memory is used at runtime by this dynamic memory allocation.

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What target audience does your product serve?

Natasha_Volkova [10]

Answer:

A target audience is the demographic of people most likely to be interested in your product or service. For example if you own a plumbing company, the target audience is property owners, both commercial and residential.

7 0

3 years ago

The ____ option must be used when running a program in order to see the results of assert statements.

Lera25 [3.4K]

Answer:

-ea

Explanation:

We can enable or disable assertions in java, by default this assertions are disabled at runtime, but we can use two commands, for example, if we want to enable assertions at various granularities, we can use the -enableassertions, or -ea, switch, if we want to disable at various granularities, is -disableassertions, or -da.

4 0

3 years ago

Please code in python and add comments to code

Gnoma [55]

#accepting input from user

n=int(input("Enter a number: "))

#entered number is stored in a temporary variable

temp=n

#initializng required variables

rev=0

dgt=0

#digits are reversed inside while loop

while(n>0):

dgt=n%10

rev=rev*10+dgt

n=n//10

#original number and its reverse are compared

if(temp==rev):

#if equal, it's a palindrome

print("It is a Palindrome")

else:

#if not equal, it's not a palindrome

print("It is not a Palindrome")

#◌⑅⃝●♡⋆♡Nåmřāthā♡⋆♡●⑅◌

4 0

2 years ago

Write a program that uses an STL List of integers. a. The program will insert two integers, 5 and 6, at the end of the list. Nex

poizon [28]

Answer:

answer:

#include <iostream>

#include<list>

using namespace std;

bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;

l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";

/*Display the list*/

cout<<endl; return 0;

}

5 0

3 years ago

Read 2 more answers

Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F

yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.

No understudy who got a confinement got an A.

No understudy who got a confinement is on the respect roll.

No understudy who got an A missed class.

No understudy who got a confinement got an A.

No understudy who got a confinement missed class

Explanation:

M(x): x missed class

An (x): x got an A.

D(x): x got a confinement.

¬∃x (A(x) ∧ M(x))

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ M(x))

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope got a confinement.

Penelope missed class.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a confinement.

Each understudy who missed class got a confinement.

Penelope is an understudy in the class.

Penelope didn't miss class.

Penelope didn't get imprisonment.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got imprisonment.

Each understudy who missed class or got imprisonment didn't get an A.

Penelope is an understudy in the class.

Penelope got an A.

Penelope didn't get repression.

M(x): x missed class

S(x): x is an understudy in the class.

D(x): x got a repression.

An (ax): x got an A.

H(x): x is on the regard roll

An (x): x got an A.

D(x): x got a repression.

∀x (H(x) → A(x)) a

¬∃x (D(x) ∧ A(x))

∴ ¬∃x (D(x) ∧ H(x))

Real.

1. ∀x (H(x) → A(x)) Hypothesis

2. c is a self-self-assured element Element definition

3. H(c) → A(c) Universal dispatch, 1, 2

4. ¬∃x (D(x) ∧ A(x)) Hypothesis

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6

8. ¬A(c) ∨ ¬D(c) Commutative law, 7

9. ¬H(c) ∨ A(c) Conditional character, 3

10. A(c) ∨ ¬H(c) Commutative law, 9

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13

4 0

3 years ago