Question

Find the cubic function given the zeroes: sqrt 2, opposite of the sqrt of 2, -2

Answer 1

$\mathsf{(x-\sqrt{2})\cdot(x+\sqrt{2})\cdot(x+2)=0}\\ \\ \mathsf{(x^2+\sqrt{2}\cdot x-\sqrt{2}\cdot x-\sqrt{2}^2)\cdot(x+2)=0}\\ \\ \mathsf{(x^2-2)\cdot(x+2)=0}\\ \\ \boxed{\mathsf{x^3+2x^2-2x-4=0}}$