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sammy [17]
3 years ago
6

Which elements in a set below are integers?12,-3/4,5,-7,2.24,14/7,9

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

12, 5, -7, 14/7, 9

Step-by-step explanation:

Integers are numbers that are either positive or negative and are whole numbers (no decimals).

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I need help with substitution​
Neporo4naja [7]

Answer:

(-7,-15)

Step-by-step explanation:

We can substitute first y in the second y. Both equations are also functions. We can merge the equations.

2x - 1 = x - 8  \\ 2x - x =  - 8 + 1 \\ x =  - 7

Substitute x = -7 in any given equations. I will choose the second equation to substitute in.

y = x - 8 \\ y =  - 7 - 8 \\ y =  - 15

<u>Answer</u><u> </u><u>Check</u>

Substitute both x and y in both equations.

- 15 = 2( - 7) - 1 \\  - 15 =  - 14 - 1 \\  - 15 =  - 15

The equation is true for (-7,-15).

- 15 =  - 7 - 8 \\  - 15 =  - 15

The second equation is true for (-7,-15).

Therefore our answer is (-7,-15)

6 0
3 years ago
Read 2 more answers
Simplify |3 − 11| − (15 ÷ 3 + 2) 2
Vikentia [17]
|-8| - (5 + 2)2
8-(7)2
8-14= -6

Follow order of operations
6 0
3 years ago
Can you help me find MAD for this
White raven [17]

Answer:

5

Step-by-step explanation:

(3+15+21+13)/4 = 13

13 - 3 = 10

15 - 13 = 2

21 - 13 = 8

13 - 13 = 0

(10+2+8+0)/4 = 5

3 0
3 years ago
As a sales person, you are paid $100 per week plus a commission of $5 per sale. If you want to earn at least $275 this week, how
dedylja [7]
275-100=175 (amount of bonus) 175÷5 (amount per bonus)= 35 total sales
8 0
2 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
My name is Ann [436]

Answer:

Vertices at (-7, 5) and (-1, 5).

Foci at (-9, 5) and (1,5).

Step-by-step explanation:

(x + 4)²/9 - (y - 5)²/16 = 1

The standard form for the equation of a hyperbola with centre (h, k) is

(x - h²)/a² - (y - k)²/b² = 1

Your hyperbola opens left/right, because it is of the form x - y.

Comparing terms, we find that

h = -4, k = 5, a = 3, y = 4

In the general equation, the coordinates of the vertices are at (h ± a, k).

Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).

The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².

c² = 9 + 16 = 25, so c = 5.

The coordinates of the foci are (-9, 5) and (1, 5).

The Figure below shows the graph of the hyperbola with its vertices and foci.

6 0
3 years ago
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