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Ket [755]
2 years ago
13

A number cube has six faces, numbered 1 to 6. John tossed two number cubes several times and added the numbers each time

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
3 0
So where's the question?
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Write a fraction for the portion of the grid that is NOT shaded.
Aneli [31]

7

15

because there are a total of 15 grid and the question asked to pick the grid that doesn't shaded

5 0
3 years ago
Read 2 more answers
I need these done as quick as possible and i have no clue what to do.
Korvikt [17]

Answer:

1. y = 4

2. x = 10

3. n = 6

4. m = 4

5. h = 2

Step-by-step explanation:

Hope this helps!!

3 0
3 years ago
Read 2 more answers
Help asap!!!!!!!
azamat

Answer:

C and D

Step-by-step explanation:

So from the equation <em>y = 1.26x + 9.49</em>  we can gather that <em>9.49</em> is an initial value because it has to be added to the number with a variable <em>( 1.26x)</em>

Because <em>1.26</em>  has a variable of <em>x  </em>and x represents a week, we know that the number<em> 1.26 </em>will increases in value depending on how many weeks have passed.

7 0
3 years ago
What is when you divide 33-55 divide by 11 will egual
SVETLANKA909090 [29]
So if you means 33-55=-22
-22/11=x

so when dividing by a negative, just divide as usual, but just make the answer negative so

-22/11=22/11 times -1/1=2 times -1=-2

the answer is -2
8 0
3 years ago
Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
2 years ago
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