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s2008m [1.1K]
3 years ago
11

What needs to be corrected in this construction of a line parallel to AB passing through C?

Mathematics
2 answers:
erica [24]3 years ago
4 0
<span>The answer would be C, as it is the only line that if it crosses though Line C it is not touching AB therefore meets the definition of being parallel to it. All other answers are touching AB and not running parallel to it.</span>
monitta3 years ago
3 0

Answer;

C) The second arc should be centered at C.

Explanation;

Assuming the goal is to construct a line parallel to AB that passes through given point C.

-Draw a line through C and across AB at an angle creating D.

- With the compass width about half of DC, and center D, draw the first arc to cross both lines.

-Using the same compass width , draw the second arc with center C.

-Then set the compass width to the lower arc (the first arc)

- Move the compass to the second arc. Mark off an arc to make point E

-Draw a straight line through C and E

Thus the line CE will be parallel to line AB

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Leo reads 14 pages in 1/3 hourWhat is the unit rate for pages per hour
pogonyaev

To determine the unit rate of pages, that is, the number of pages Leo reads in one hour you can use cross multiplication

1/3h _____14 pages

1h______x pages

\begin{gathered} \frac{14}{\frac{1}{3}}=\frac{x}{1} \\ 14\cdot3=x \\ x=42 \end{gathered}

Leo reads 42pages/hour

7 0
1 year ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
olasank [31]

Answer:  a_n=2(5)^{n-2}

<u>Step-by-step explanation:</u>

The explicit rule for a geometric sequence is: a_n=a_1(r)^{n-1}\quad \text{where}\ a_1\ \text{is the first term and r is the ratio}

The information provided is: a₁ = \dfrac{2}{5}  and  r = 5

a_n=\dfrac{2}{5}(5)^{n - 1}\\\\.\quad = 2(5)^{n-2}

4 0
3 years ago
Which of the following will result in a rational answer?
horrorfan [7]

Answer:

multiplying a fraction by a repeating decimal

Step-by-step explanation:

any fraction is rational

any repeating decimal is rational

therefore, product of the two would be rational

3 0
3 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
What is 3/4 divided by 7/12 as a fraction?
Yakvenalex [24]

Answer:

9/7

Step-by-step explanation:

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7 0
1 year ago
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