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Blizzard [7]
3 years ago
14

What is the average acceleration of the particle within the time interval 1 second to 3 seconds? A. -1 meter/second2 B. 0 meters

/second2 C. 1 meter/second2 D. 1.5 meters/second2 E. 2 meters/second2
Physics
1 answer:
yuradex [85]3 years ago
6 0

The answer is Option B: 0 meters/seconds^2

A= velocity/time

Points: ( 1,3) (3,3)

Velocity: 3-3=0

Time: 3-1=2

0/2= 0 meters/seconds^2

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What is primary sex organs called
Ostrovityanka [42]
The primary sex organs for men are called testes and ovaries for the women. They produce sex cells called gametes and they secrete sex hormones.
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3 years ago
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A 34.1-mL sample of benzene at 20.8°C was cooled to its melting point, 5.5 °C, and then frozen at 5.5 °C. Calculate the quantity
posledela

Answer:

4541.8 J

Explanation:

First we find the mass of benzene available

mass = density x volume

         = 0.867 x 34.1

         = 29.5647 g

Then we find the amount of heat transferred by two processes:

heat tranferred = heat lost during temp drop + heat lost during freezing

                         = mcΔT + mL

                         = 29.5647 x 1.74 x (20.8 - 5.5) + 29.5647 x 127

                         = 4541.7883434 J

                         = 4541.8 J

                         

3 0
3 years ago
Read 2 more answers
A 0.260 m radius, 525 turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a
Sophie [7]

Answer:

B = 0.37T

Explanation:

In order to calculate the needed magnitude of the magnetic force you use the following formula, which calculate the induced emf of the solenoid when there is a change in the magnetic flux:

emf=-N\frac{\Delta \Phi_B}{\Delta t}=-N\frac{\Delta (BAcos\theta)}{\Delta t}       (1)

emf: induced voltage in the solenoid = 10,000V

N: turns of the solenoid = 525

ФB: magnetic flux

B: magnitude of the magnetic field = ?

A: cross-sectional area of the solenoid = π*r^2

r: radius of the cross-sectional area = 0.260m

Δt: interval time of the change of the magnetic flux = 4.17ms = 4.17*10^-3s

First, you have the magnetic field direction perpendicular to the plane of the solenoid, after, the angle between them is 90°  (quarter of a revolution)

In the equation (1) the only parameter that changes on time is the angle, then, you can solve for B from the equation (1):

emf=-NBA\frac{cos(90\°)-cos(0\°)}{\Delta t}=\frac{NBA}{\Delta t}\\\\B=\frac{(\Delta t)(emf)}{NA}=\frac{(\Delta t)(emf)}{N(\pi r^2)}\\\\

Finally, you replace the values of the parameters to calculate B:

B=\frac{(4.17*10^{-3}s)(10000V)}{(525)(\pi(0.260m)^2)}=0.37T

The strength of the magnetic field is 0.37T

7 0
3 years ago
A car with an initial speed of 23.4 km/h accelerates at a uniform rate of 0.90 m/s2 for 4.0 s.
ss7ja [257]
Final velocity is 10.1 m/s
5 0
3 years ago
How far does a plane fly in 10.0 s while its velocity is changing from 175 m/s to 105 m/s at a uniform rate of
gizmo_the_mogwai [7]

Answer:

1400 m

Explanation:

Given:

v₀ = 175 m/s

v = 105 m/s

t = 10.0 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (105 m/s + 175 m/s) (10.0 s)

Δx = 1400 m

6 0
3 years ago
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