A. How much work is being done to hold the beam in place?
Work is the product of Force and Displacement. Since there
is no Displacement involved in just holding the beam in place, hence the work
is zero.
B. How much work was done to lift the beam?
In this case, force is simply equal to weight or mass
times gravity. Hence the work is:
Work = weight * displacement
Work = 500 lbf * 100 ft
Work = 50,000 lbf * ft
C. How much work would it take if the steel beam were
raised from 100 ft to 200ft?
The displacement is still 100 ft since 200 – 100 = 100 ft,
hence the work done is still similar in B which is:
<span>Work = 50,000 lbf * ft</span>
Interesting I guess not much you put
Answer:
983.400345675 hits per second
Explanation:
Radius = 14.2 cm
Record turn rate = 33 rev/min
Bump separation = 0.499 mm
Circumference of the record = 
Number of bumps in the groove = 
The rate which the bumps hit the stylus = 
The rate at which the bumps hit the stylus 983.400345675 hits per second
Answer:
Counterclockwise
Explanation:
We need to calculate the clocwkise and the counterclockwise torque.
The clockwise torque is the one generated by the child sitting on the right. This torque is given by:

where
is the force exerted by the child (his weight)
d = 1.8 m is the distance from the pivot point
So, the clockwise torque is

The counterclockwise torque is the one generated by the adult pushing on the left, and it is given by

where
F = 151 N is the force applied
d = 3.0 m is the distance from the pivot
Substituting,

So, the net torque is

And since the counterclockwise momentum is greater than the clockwise one, the teeter-totter will rotate counterclockwise.
Answer:
the energy of the photons is greater than the work function of the zinc oxide.
h f> = Ф
Explanation:
In this experiment on the photoelectric effect, it is explained by the Einstein relation that considers the light beam formed by discrete energy packages.
K_max = h f - Ф
in the exercise phase, they indicate that different wavelengths can inject electrons, so the energy of the photons is greater than the work function of the zinc oxide.
h f > = Ф