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olya-2409 [2.1K]
3 years ago
7

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

th the same mass as an electron but the opposite charge ( e). Express your answer in vector form. Do not enter units in your expression.
Required:
a. If a positron is accelerated by a constant electric field, find the acceleration of the positron.
b. Assuming the positron started from rest, find the velocity of the positron
Physics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

a) a = + 1,758 10¹¹ m / s ,  b)  = √ (2 1,758 10¹¹ E x)

Explanation:

a) A charged particle is an electric field undergoing force given by the expression

          F = qE

where q is the charge of the paticle and E electric field.

In this case we are told that the particle is positron

         q = + 1.6 10⁻¹⁹ C

let's calculate the force

         F = + 1.6 10⁻¹⁹ E

we write the positive sign, to show that the particle accelerates in the same direction of the electric field

let's write Newton's second law to find the acceleration

    F = ma

     a = F / m

     a = + 1.6 10-19 / 9.1 10-31 E

     a = + 1,758 10¹¹ m / s

b) the velocity of the particle starting from rest

       v² = v₀² + 2 a x

       v = √ (2 1,758 10¹¹ E x)

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1. In what year did India (our second most populous country) begin to produce more energy than Spain?
choli [55]

Answers:

<h2>1) Sometime in 2014 </h2>

As we can see in the graph in 2014 there is an intersection between the lines that represent the wind energy production of Spain and India, then the production of India is increased, while that of Spain remains constant.

<h2>2) Germany </h2>

As we can see in the graph in 2000 Germany was the number 1 producer of gigawatts of wind energy. In addition it is observed a rapid growth and increase in production compared to the other countries.

<h2>3) In 2006, America was producing over 10 GW and began a steep climb in wind energy production.</h2>

In 1997, America began with a constant and very small energy production, which was growing gradually until 2006, when its rapid growth in production began to exceed the other countries shown in the graph.

<h2>4) Years</h2>

When a function is plotted, generally the independent variable, whose value is previously set, is represented on the X axis.

In this sense, the variable found on the X axis of this graph is Years.

<h2>5) Wind Energy Capacity </h2>

When a function is plotted, generally the dependent variable (which is generated from the independent variable) is represented on the Y axis.

In this sense, the variable found on the Y axis of this graph is Wind Energy Capacity.

<h2>6) Gigawatts (GW) </h2>

We already know the dependent variable in this <u>Wind Energy Capacity vs Years</u> graph is Wind Energy Capacity, and its Unit is Gigawatts (GW).

Where 1GW=10^{6} W

<h2>7) Both onshore and offshore wind sources </h2>

When we talk about scientific experimentation and representing data, the Control Variable is the one that remains constant (it does not change during the investigation).  

According to the explanation above, the option that fits with this characteristic is: Both onshore and offshore wind sources

<h2>8) 55 GW </h2>

If we want to make a linear interpolation to estimate how much wind energy capacity was there in the United States in the middle of 2011, firstly we need to <u>find two points where the value we want to find is in the middle.</u>

These points (X,Y) are:

P1: (2011,48) and P2: (2012,60)

Where X1:2011, Y1:48, X2:2012, Y2:60

Now we find the <u>slope</u> m of the line with the following equation:

m=\frac{Y2 - Y1}{X2 - X1}

m=\frac{60 - 48}{2012 - 2011}=12

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> b with one of the given points (we will use P1):

Y=mX+b

48=12(2011)+b

b=-24084

With this value and the slope, we can find Y for X=2011.5 (we need to know the wind capacity in the middle of 2011):

Y=(12)(2011.5)-24084

Y=54 This is the e<u>stimated result</u> 54 GW, and the option that is near this value is 55 GW

<h2>9) 36 GW </h2>

In this case we will apply a similar method as the previous answer, but estimating a prediction:

Let's find two points near the value we want to find. These points (X,Y) are:

P1: (2014,22) and P2: (2016,29)

Where X1:2014, Y1:22, X2:2016, Y2:29

Now we find the <u>slope</u> m of the line with the following equation:

m=\frac{Y2 - Y1}{X2 - X1}

m=\frac{29 - 22}{2016 - 2014}=\frac{7}{2}

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> b with one of the given points (we will use P2):

Y=mX+b

29=\frac{7}{2}(2016)+b

b=-7027

With this value and the slope, we can find Y for X=2020 (we need to estimate the expected wind capacity in 2020):

Y=\frac{7}{2}(2020)-7027

Y=43 This is the e<u>stimated result</u> 43 GW (note linear extrapolation is not as accurate as other methods), and the option that is near this value is 36 GW

<h2>10) Additional 7 GW/Year</h2>

In this case we will use the equation of the slope:

m=\frac{Y2 - Y1}{X2 - X1}

With the following points:

P1: (2009,35) and P2: (2016,82)

m=\frac{82 - 35}{2016 - 2009}

m=6.7 \approx 7

Therefore, the correct option is Additional 35 GW/Year

4 0
3 years ago
Suppose you must design an experiment to test how a paper airplane's shape affects the distance it will fly. Your plane must fly
Rina8888 [55]

Answer:

Explanation:

Your plane must fly halfway across your classroom to get the best grade. The teacher reminds you to use both imagination and logical reasoning in your design. Write a procedure for an experiment that tests how a paper airplane's shape affects the distance it will fly. Then, describe how you might use both ...

5 0
3 years ago
Read 2 more answers
A hunter stands on a frozen pond (frictionless) and fires a 4.20g bullet at 965m/s horizontally.The mass of hunter + gun is 72.5
Afina-wow [57]

Answer:

The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

Explanation:

Given;

mass of bullet, m₁ = 4.2 g = 0.0042 kg

mass of hunter + gun = 72.5 kg

velocity of the bullet, u = 965 m/s

Momentum of the bullet when it was fired;

P = mv

P = 0.0042 x 965

P = 4.053 kg.m/s

Determine the recoil velocity of the hunter.

Total momentum = sum of the individual momenta

Total momentum = momentum of the bullet + momentum of the hunter

Apply the principle of conservation of momentum, sum of the momentum is equal to zero.

P_{hunter} + P_{bullet} = 0\\\\P_{hunter}  = -P_{bullet}\\\\72.5v = -4.053\\\\v = \frac{-4.053}{72.5} \\\\v = - 0.056 \ m/s\\\\Thus, the \ recoil \ velocity \ of \ the \ hunter \ is \ 0.056 \ m/s, \ in \ opposite \ direction \ of \ the \ bullet.

Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

6 0
4 years ago
A 60 kg runner has 1500 J of kinetic energy. How fast is he moving?
Lapatulllka [165]

The speed with which runner is running is 7.07m/s

<u>Explanation:</u>

Given:

Mass, m = 60kg

Kinetic energy, KE = 1500J

Velocity, v = ?

We know,

Kinetic energy = \frac{1}{2} mv^2

On substituting the value we get,

1500 = \frac{1}{2} X 60 X v^2\\\\v^2 = 50\\\\v = 7.07 m/s

Therefore, the speed with which runner is running is 7.07m/s

7 0
3 years ago
Who expressed particles by wave equations?
ehidna [41]
I believe it was famous quantum physicist <span>Erwin Schrödinger
</span> 
7 0
3 years ago
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