Answer:
5 m
Explanation:
30 m/s / 6.0 cycles/s = 5 m/cycle
Answer:
29.4m/s
Explanation:
Given parameters:
Time = 3s
Unknown:
Average velocity = ?
Solution:
To solve this problem, we use the expression below:
v = u + gt
v is the average velocity
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time
So;
v = 0 + (9.8 x 3) = 29.4m/s
Answer: 2704 J
Given :
mass = 200 g
velocity = 5.2 m/s
kinetic energy = 1/2 mv^2
= 1/2 * 200 * (5.2)^2
100 * 27.04
2704 J
Answer:
a) 1.58 kg s^{-1}
b) x_m e^{-1.58t} x_m is initial amplitude
c) 5 kg s^{-1}
Explanation:
given data:
mass =0.5 kg
k = 12.5 N/m
from the data given
a)
b)
where x_m is initial amplitude
c) critical damping amplitude
Answer:
A, B, D.
Explanation:
If Jamy pushes on Anita, then by Newton's 3rd Law there will be a reaction force equal in magnitude and opposite in direction. This means that A and D are correct, while C, E, F and G are incorrect. Since the magnitude of any of these forces can be calculated with Newton's 2nd Law, F=ma for either Jamy or Anita, this means that B is correct.