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kobusy [5.1K]
3 years ago
7

Suppose you must design an experiment to test how a paper airplane's shape affects the distance it will fly. Your plane must fly

halfway across your classroom to get the best grade. The teacher reminds you to use both imagination and logical reasoning in your design.
Write a procedure for an experiment that tests how a paper airplane's shape affects the distance it will fly. Then, describe how you might use both imagination and logical reasoning to increase your chances of discovering an airplane shape that will fly at least halfway across the classroom.
Physics
2 answers:
Rina8888 [55]3 years ago
5 0

Answer:

Explanation:

Your plane must fly halfway across your classroom to get the best grade. The teacher reminds you to use both imagination and logical reasoning in your design. Write a procedure for an experiment that tests how a paper airplane's shape affects the distance it will fly. Then, describe how you might use both ...

elixir [45]3 years ago
3 0

Answer:

The larger the paper airplane the more it will weigh, the more it weighs the more lift will be needed to keep it flying. Eventually, the weight will become greater than the lift and the paper airplane will decend to the ground. In adition the larger the paper airplane the larger its wings can be

Explanation:

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An electron moving in a wire collides again and again with atoms and travels an average distance between collisions that is call
hoa [83]

Explanation:

A substance with a short , medium, free path has improved electron flow resistance and a higher electrical resistance . Heat applications impose more molecular chaos on all materials and shorten the track further, increasing resistance of most materials. So, just refresh the material to expand the course. In certain materials, when cooled to the minimum temperature, the conductivity is substantially increased.

4 0
3 years ago
What is the time constant of a series circuit where the capacitor is 0.330μF and the resistor is 10Ω ?
PtichkaEL [24]

Answer:

\tau=3.3*10^{-6}s

Explanation:

Take at look to the picture I attached you, using Kirchhoff's current law we get:

C*\frac{dV}{dt}+\frac{V}{R}=0

This is a separable first order differential equation, let's solve it step by step:

Express the equation this way:

\frac{dV}{V}=-\frac{1}{RC}dt

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

\int\limits^V_v {\frac{dV}{V} } =-\int\limits^t_0 {\frac{1}{RC} } \, dt

Evaluating the integrals:

ln(\frac{V}{v})=e^{\frac{-t}{RC} }

natural logarithm to both sides in order to isolate V:

V(t)=ve^{-\frac{t}{RC} }

Where the term RC is called time constant and is given by:

\tau=R*C=10*(0.330*10^{-6})=3.3*10^{-6}s

3 0
3 years ago
A car initially traveling at 15 m/s North accelerates to 25 m/s North in 4 seconds. The magnitude of the average acceleration is
GarryVolchara [31]

The average acceleration of the car as it accelerates from 15 m/s to 25 m/s will be 2.5 m/s².

<h3>What is Average acceleration?</h3>

Average acceleration is the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given that a car is traveling at 15 m/s in north direction and in 4 seconds it accelerates to 25 m/s in the north direction only. Therefore, we can write -

initial velocity [u] = 15 m/s

final velocity [v] = 25 m/s

time taken [Δt] = 4 s

The magnitude of the average acceleration can be calculated as follows-

a = Δv/Δt

Δv = v - u = 25 - 15

Δv = 10 m/s

Therefore -

a = 10/4

a = 2.5 m/s².

Therefore, the average acceleration of the car will be 2.5 m/s².

To solve more questions on Acceleration, visit the link below-

brainly.com/question/21300541

#SPJ1

4 0
1 year ago
Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec
salantis [7]

Answer:

Value of angle between vector a and b is 56.30^{\circ}.

Explanation:

Vectors a and b have scalar product 6.00

Let \theta be the angle between a and b.

\vec{a}.\vec{b} = 6

ab cos \theta = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

\vec{a} \times\vec{b} = 9

ab sin \theta = 9 ...(2)

Dividing equation (2) by (1) we get

\frac{ab sin \theta}{ab cos \theta}  = \frac{9}{6}

tan \theta = 1.5

\theta = tan ^{-1} (1.5)

\theta = 56.30^{\circ}

Thus, value of angle between vector a and b is 56.30^{\circ}.

3 0
4 years ago
Firecrackers 1 and 2 are 600 m apart. You are standing exactly halfway between them. Bob is standing 300 m on the other side of
Afina-wow [57]

Answer:

the same time

Explanation:

since the speed of light is very fast (3×10^8 ms^-1) the difference in time arrived from firecrackers A and B to Bob is negligible, and our brain can distinguish such small time difference,l.

6 0
3 years ago
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