Omials GCF of 96x5 and 64x2?
1 answer:
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Options:
A. Players at school 1 typically spent more time in the weight room than players at school 2.
B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.
C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.
D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.
(See attachment for the box plots)
Answer:
C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.
Step-by-step explanation:
The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8
School 2 has a median of 9.
As we can see, the median for school 1 is less than the median of school 2.
Interquartile range is the range of the box.
Interquartile range for school 1 = 10 - 4 = 6
Interquartile range for school 2 = 13 - 6 = 6
As we can also see, the interquartile range for school 1 and that of school 2 are equal.
