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BaLLatris [955]
2 years ago
11

The equation of the line which passes through the point (0,5) and has a gradient of 4 is

Mathematics
1 answer:
const2013 [10]2 years ago
6 0

Answer:

y = 4x + 5

Step-by-step explanation:

slope = m = 4

y-intercept = b = 5

y = mx + b

y = 4x + 5

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What is 12 divided by 6/7
Naddik [55]
What is the easiest way to divide whole numbers to fractions?
Just follow these two easy steps:
1. Multiply the whole number  to the denominator of the fraction. In other words, the bottom number of the fraction will be multiplied to the whole number, like this:

12 ÷ 6/7 = n
 <u>   6    </u>
7 x 12
You will have 6/ 84.
2. Simplify.
6  = 1, 2, 3, 6
84= 1, 2, 3, 4, 6, 7, 12, 14, 21, 42, 84

the GCF is 6.  divide both numbers by 6, so the answer will be 1/14.

You can also get the reciprocal and proceed to multiplication , like this: (12/1 is the fractional form or the whole number 12.)
 1/12 x 6/7=n
that makes 6/84 or 1/14.
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Describe the pattern in each sequence and determine the next term of the sequence
sladkih [1.3K]

Sorry misspelt every word , i’m trying to do this fast. Thank you

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3 years ago
Which of the following is the solution to the equation x + 6.8 = 53.5?
gregori [183]
X+6.8=53.5
x=53.5-6.8
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3 years ago
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The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
3 years ago
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