Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So

Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So

Find the probability that bridge B was used.

0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Top answer · 0 votes
f(g(x))=362−x−2k f(g(x))=x→362−x−2k=x→x2−2x(1−k)−4(k−9)=0 Solution for x are equal if and only if discriminant Δ=0 4(1−k)2+16(k−9)=0 ... More
Answer:
18
Step-by-step explanation:
xy + 4 = 40
xy = 40 - 4
xy = 36
What two numbers can b multiplied to give 36? Then add them.
9 + 4 = 13
18 + 2 = 20
6 + 6 = 12
12 + 3 = 15
The odd option is 18
Answer:
6
Step-by-step explanation:
root the 216 as it is a cube
:edge *edge *edge =volume
Since all edges are the same, just root it
You would divide -204 divide it by -17 and you would get 12
X=12