This is the standard form equation 
What is the ellipse?
The equation for an ellipse is typically written as x² a² + y² b² = 1. x² a² + y² b² = 1. An ellipse with its origin at the center is defined by this equation. The ellipse is stretched further in both the horizontal and vertical directions if a > b, a > b, and if b > a, b > a, respectively.
The standard form of the equation of an ellipse with center (h, k)and major axis parallel to the x-axis is:
where,
a > b
the length of the major axis is 2a
the coordinates of the vertices are (h±a,k)
the length of the minor axis is 2b
the coordinates of the co-vertices are (h,k±b)
the coordinates of the foci are (h±c,k),
where c² = a² − b².
so,
Hence, this is the standard form equation .
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This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
All you can do to this expression is simplify.
You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:
Therefore your end result is:
Answer:
x=4 y=0
Step-by-step explanation:
You add the two equations together to get 3x=12. You derive x=4 and y=0 from that.
Answer:
don't get what
Step-by-step explanation:
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