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4 years ago

Algebraic expression for 8+6q+q

1 answer:

3 0

All you can do to this expression is simplify.

You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:

$6q + 1q = 7q$

Therefore your end result is:

$8 +7q$

You might be interested in

Write the ratio of dogs to cats in simplest form.

vlada-n [284]

12/16 becomes 6/8 which later becomes 3/4.

So,

The ratio of dogs to cats in simplest form is 3:4 [Option 4]

Hope it helps!

6 0

3 years ago

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

alina1380 [7]

Answer:

The answer is $x=a^{-1}cb^{-1}$ .

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element $g\in G$ there exist another element, denoted by $g^{-1}$ such that $gg^{-1}=e$ , where $e$ stands for the identity element of G.

So, given the equality $axb=c$ we make a left multiplication by $a^{-1}$ and we obtain:

$a^{-1}axb =a^{-1}c.$

But, $a^{-1}axb = exb = xb$ . Hence, $xb = a^{-1}c$ .

Now, in the equality $xb = a^{-1}c$ we make a right multiplication by $b^{-1}$ , and we obtain

$xbb^{-1} = a^{-1}cb^{-1}$ .

Recall that $bb^{-1}=e$ and $xe=x$ . Therefore,

$x=a^{-1}cb^{-1}$ .

6 0

3 years ago

A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32

zavuch27 [327]

$Hypotenuse =39cm$ of right angle triangle! .

<u>Step-by-step explanation:</u>

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the length of the hypotenuse is 7.5 centimeters. We need to find:

We have , One length as 32 cm and other as 25 cm , as

$Perpendicular = 32cm\\Base=25cm$

By Pythagoras Theorem ,

⇒ $Hypotenuse^2 = Perpendicular^2+Base^2$

⇒ $Hypotenuse^2 =32^2+22^2$

⇒ $\sqrt{Hypotenuse^2} =\sqrt{1024+484}$

⇒ $Hypotenuse =39cm$

So , $Hypotenuse =39cm$ of right angle triangle! .

4 0

3 years ago

Read 2 more answers

Mark tosses a coin 25 times. What is the probability that it lands on heads exactly seven times?

mezya [45]

Answer:

1.43%

Step-by-step explanation:

we have that we can solve it by means of binomial, in this case m = 25. Also the probability of head is 50%. we need to know when it falls 7 times, therefore x = 7

the formula is:

P (x) = mCx * p ^ x * q ^ (m-x)

we know that p is 0.5 therefore q is equal to 0.5, replacing:

P (7) = 25C7 * 0.5 ^ 7 * 0.5 ^ (25-7)

P (7) = 25! / (7! * (25-7)!) * 0.5 ^ 7 * 0.5 ^ (25-7)

P = 0.0143

that is, the probability is 1.43%

6 0

3 years ago

The two figures above are congruent. Find the measure of the angle that isn't labeled on either figure.

harkovskaia [24]

Answer:Idk sry

Step-by-step explanation:

7 0

3 years ago