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user100 [1]
3 years ago
14

Natalie is skiing along a circular ski trail that has a radius of 2.6 km. She starts at the 3-o'clock position and travels in th

e CCW direction. Natalie stops skiing when she is 0.942 km to the right and 2.423 km above the center of the ski trail. Imagine an angle with its vertex at the center of the circular ski trail that subtends Natalie's path.
a. How many radians has the angle swept out since Natalie started skiing? ______radians
b. How many km has Natalie skied since she started skiing? _________km

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

  • 1.20 radians
  • 3.12 km

Step-by-step explanation:

a. The tangent of the central angle is the ratio ...

  tan(θ) = (2.423 km)/(0.942 km) . . . . . definition of tangent

  θ = arctan(2.423/.942) ≈ 1.200 radians

__

b. The length of the arc is ...

  s = rθ = (2.6 km)(1.2 radians) = 3.12 km

_____

The attached output from a graphics program shows the angle as 68.76°. Multiplying by π/180°, we can convert that to radians:

  θ = 68.76π/180 = 216.0/180 = 1.200 radians

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2. Maria is monitoring the temperature of
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Here, we are required to determine after how many minutes will the two substances be at the same temperature.

The equation of when the two substances will be at the same temperature and the solution are as follows;

(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).

(b) The solution is, x = 3.285minutes.

For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;

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For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;

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(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).

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The equation is therefore;.

96.2 + 1.5(x) = 98.5 + 0.8(x)

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Read more:

brainly.com/question/20248109

5 0
2 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
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Answer:

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Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

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It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

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This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

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In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

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