Answer:
Quel est le nom de la prof?
Step-by-step explanation:
The answer is 0
Let's solve your equation step-by-step.
3(|v−3|)=9
Step 1: Divide both sides by 3.
3(|v−3|)3=93
|v−3|=3
Step 2: Solve Absolute Value.
|v−3|=3
We know either v−3=3orv−3=−3
v−3=3(Possibility 1)
v−3+3=3+3(Add 3 to both sides)
v=6
v−3=−3(Possibility 2)
v−3+3=−3+3(Add 3 to both sides)
v=0
Answer:
v=6 or v=0
solve for "P" to find the Principal
Hey there! Do you need any help with a question or are you just Spaming
Problem 1)
The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.
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Problem 2)
log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]
Answer is choice D
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Problem 3)
log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)
This matches with choice B
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Problem 4)
Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9
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Problem 5)
Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5
This means choice A is the answer