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maks197457 [2]
3 years ago
11

Solve (x-5)^2=3 apex!!!

Mathematics
2 answers:
slega [8]3 years ago
8 0
The answer would be 6.5
Anna71 [15]3 years ago
7 0

Answer:

x = 5 + √3 and  x = 5 - √3

Step-by-step explanation:

 First take the square root of both sides...

x - 5 = ±√3

Now add 5 to both sides....

x = 5 ± √3

so x = 5 + √3   and x = 5 - √3

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3.3^(2x+1)-103^x+1=0 need value of x
photoshop1234 [79]

Answer:

The value of x is approximately -1.531.

Step-by-step explanation:

Let 3.3^{2\cdot x + 1}-103^{x+1} = 0, we proceed to solve this expression by algebraic means:

1) 3.3^{2\cdot x + 1}-103^{x+1} = 0  Given

2) 3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0 a^{b}\cdot a^{c} = a^{b+c}

3) (3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}

4) (3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}/Commutative property

5) \left[\left(\frac{3.3}{\sqrt{103}}\right)^{x}\right] ^{2}-\frac{103}{3.3} = 0 Existence of multiplicative inverse/Definition of division/Modulative property/a^{b}\cdot a^{c} = a^{b+c}

6) \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3} Existence of additive inverse/Modulative property/(a^{b})^{c} = a^{b\cdot c}

7) \log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3} Definition of logarithm.

8) 2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}     \log_{b} a^{c} = c\cdot \log_{b} a

9) 2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3      \log_{b} \frac{a}{d}

10) x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3     \log_{b} a^{c} = c\cdot \log_{b} a/Associative property

11) x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}   Existence of multiplicative inverse/Definition of division/Modulative property

12) x \approx -1.531  Result

The value of x is approximately -1.531.

4 0
3 years ago
Can someone please solve FAST I have 5 minutes
Hunter-Best [27]

Answer:

no time left sorry

Step-by-step explanation:

7 0
3 years ago
The perimeter of the base of a square pyramid is 16 feet and it stands 20 ft tall. Calculate the volume.​
Vikentia [17]

Answer: 1706.67 feet

Step-by-step explanation:

Formula: Volume = \frac{1}{3} \alpha^{2}h

a is the length of the base's edge and h is the height. Since 16 is the length we would square it as it is the length, then we would multiply it by the height which is 20 ft.

<u>Steps: Multiply</u>

Volume = \frac{1}{3} \alpha^{2}h

= \frac{1}{3} * 16^{2} * 20

= 1706.67 feet

~I hope I helped you :)~

6 0
3 years ago
What two integers does Square root of 50 fall between?
il63 [147K]
It falls between 6 and 8
7 0
3 years ago
X = y^2 - 1
ohaa [14]

Answer:  The correct option is (B) 2y^2-y-6=0.

Step-by-step explanation:  We are given the following system of equations :

x=y^2-1~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\2x-y=4~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

We are to find the equation that could be the result of using substitution to solve the above system.

Substituting the value of x from equation (i) in equation (ii), we get

2x-y=4\\\\\Rightarrow 2(y^2-1)-y=4\\\\\Rightarrow 2y^2-2-y=4\\\\\Rightarrow 2y^2-y-2-4=0\\\\\Rightarrow 2y^2-y-6=0.

Thus, the required equation is 2y^2-y-6=0.

Option (B) is CORRECT.

5 0
3 years ago
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