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Vera_Pavlovna [14]
4 years ago
5

Ball-Bearings, Inc. produces ball bearings automatically on a Kronar BBX machine. For one of the ball bearings, the mean diamete

r is set at 20.00 mm (millimeters). The standard deviation of the production over a long period of time was computed to be 0.150 mm. What percent of the ball bearings will have diameters of 20.27 mm or more
Mathematics
1 answer:
kherson [118]4 years ago
3 0

Answer:

3.6% of the ball bearings will have diameters of 20.27 mm or more.

Step-by-step explanation:

We can calculate this proportion using the z-score.

We have a normal distribution with mean 20.00 mm and standard deviation of 0.150 mm.

The value for X is 20.27 mm.

Then, the z-score and its associated probability are:

z=\dfrac{X-\mu}{\sigma}=\dfrac{20.27-20}{0.15}=\dfrac{0.27}{0.15}=1.8\\\\\\P(X>20.27)=P(z>1.8)=0.036=3.6\%

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Use a factor and zero product property to solve the following equation 6x(x+4)=0
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What are the x and y-intercepts of the line described by the equation?
KiRa [710]

Answer:

x-int (6.2, 0)

y-int (0, 3.1)

Step-by-step explanation:

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y-intercept is found when x = 0.

Step 1: Define equation

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Step 2: Find x-intercept

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6 0
3 years ago
A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i
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Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

W=\frac{1}{2}kx^2

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solving in terms of k we have

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