Ask question

Ask question

All categories

4 years ago

7

At the grocery store Ayla buys1 1/3 pounds of ground turkey .Tasha buys 2 times as much ground turkey . How much ground turkey d

oes Tasha buy

1 answer:

viktelen [127]4 years ago

4 0

Answer:

2 2/3 lbs

Step-by-step explanation:

Convert Alya's mixed number to an improper fraction

3*1+1 = 4/3

multiply 4/3 times 2/1

4*2 = 8

3*1 = 3

8/3 - convert back to mixed number

8/3 = 2 2/3

You might be interested in

Please help i need the answer asap!!!

IrinaK [193]

Answer:

35 cm

Step-by-step explanation:

You can use the Cosine Rule to find the length of a side when two sides and the included angle are given.

a² = b² + c² - 2bc cos A

a² = (36²) + (52²) - 2(36)(52) cos 42°

a² = (1296) + (2704) - (3744)(0.7431448255)

a² = (4000) - (2782)

a² = 1218

a = ✓1218

a = 34.9 cm

7 0

3 years ago

Jake is comparing the prices of two laundry service companies. Company A charges $20 per load and an additional $8 as service ch

snow_lady [41]

Equation for company a: y=20x+8
Equation for company b: y=24x+4
Company A would be cheaper for 5 loads of laundry, because it is $108 dollars opposed to $124 which is what company b would charge for 5 loads.
$32 dollars is saved by using the services of company A instead of company B to clean 9 loads of laundry.

3 0

4 years ago

Serhud [2]

Among all students, sports is, by far, the most popular activity and watching TV is the least popular.

3 0

4 years ago

Solve the system of equations. 2x+2y+7z=9, 2x+6y+5z=7, 5x+2y+4z=9. a.x=3 y=-2 z=3 b.x=1 y=0 z=1 c.x=2 y=-1 z=0 d. x=0 y=1 z=2

ki77a [65]

The answer is B

Hope this helps.

6 0

4 years ago

Let vector F = (6 x^2 y + 2 y^3 + 4 e^x) i + (7 e^{y^2} + 54 x) j . Consider the line integral of vector F around the circle of

balu736 [363]

Denote the circle of radius $a$ by $C$ . $C$ is simple and closed, so by Green's theorem the line integral reduces to a double integral over the interior of $C$ (call it $D$ ):

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_C(6x^2y+2y^3+4e^x)\,\mathrm dx+(7e^{y^2}+54x)\,\mathrm dy$

$=\displaystyle\iint_D\left(\frac{\partial(7e^{y^2}+54x)}{\partial x}-\frac{\partial(6x^2y+2y^3+4e^x)}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy$

$D$ is a circle of radius $a$ , so we can write the double integral in polar coordinates as

$\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^a(54-6r^2)r\,\mathrm dr\,\mathrm d\theta$

a. For $a=1$ , we have

$\displaystyle\int_0^{2\pi}\int_0^1(54-6r^2)r\,\mathrm dr\,\mathrm d\theta=2\pi\int_0^1(54r-6r^3)\,\mathrm dr=\boxed{51\pi}$

b. Let $I(a)$ denote the integral with unknown parameter $a$ ,

$I(a)=12\pi\int_0^a(9r-r^3)\,\mathrm dr\,\mathrm d\theta$

By the fundamental theorem of calculus,

$I'(a)=12\pi(9a-a^3)$

$I(a)$ has critical points when

$12\pi(9a-a^3)=12\pi a(9-a^2)=0\implies a=0,a=\pm3$

If $a=0$ , then line integral is 0, so we ignore that critical point. For the other two, we would find $I(\pm3)=243\pi$ .

8 0

3 years ago